Let the two numbers be x and y
x + y = 5(x-y)
x + y = 5x -5y
6y = 4x
x= (6/4)y
x= (3/2)y
there the ratio is 3/2
You have to find the area of both the square and rectangle. use the formula A=wl
square = 3x3 = 9
rectangle = 10x3 = 30
area= 39 (i think)
Sorry, I know it's a little late.The answer is -6a^2 b^4 c^3
X^2 + y^2 = 8
X-y=0 so x = y
replace x = y into X^2 + y^2 = 8
y^2 + y^2 = 8
2y^2 = 8
y^2 = 8/2
y^2 = 4
y = - 2 and y = 2
because x = y
so x = - 2 and x = 2
solutions:
x= - 2 and x = + 2
y= - 2 and y = + 2
The formula is: A=1/2 h (base one + base two)
<span>Plug in your numbers and you will get the area.</span>