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3 years ago

The length of a rectangle is 11 in. longer than its width. The perimeter of the rectangle is 86 in.

1 answer:

4 0

P = 2(L + W)
P = 86
L = W + 11

86 = 2(W + 11 + W)
86 = 2(2W + 11)
86 = 4W + 22
86 - 22 = 4W
64 = 4W
64/4 = W
16 = W

L = W + 11
L = 16 + 11
L = 27 <====

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3 years ago

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3 years ago

Will Mark Brainlest helpppp

Anvisha [2.4K]

Answer:

R = $\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]$

Step-by-step explanation:

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R = $\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right]$ - $\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right]$ = $\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right]$

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3 years ago