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siniylev [52]
3 years ago
12

How do you graph y=2x+4 on a graph​

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

y =7 i think. idk im bad at math sorry. lol

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Help me please thanks​
horrorfan [7]

Answer:

325m = c

Step-by-step explanation:

Each meeting room has 325 chairs.

Since we don't know how many meeting rooms there are, the number is replaced with the variable, m.

An equation is a problem with an equals sign so you need to put what it would equal.

Since you don't know how many meeting rooms there are you use the variable, c which represents the total number of chairs.

8 0
2 years ago
What is the most direct use of a compass in geometric constructions
lora16 [44]

Answer:

The most direct use of a compass in any geometric constructions are to draw arcs of a given size.

Step-by-step explanation:

6 0
3 years ago
bailey was mixing some instant pudding.the directions said add 2 cups of milk to the contents of package.the only measuring cup
Dennis_Churaev [7]

Answer:

about 3.3 times or 3 1/3 times

Step-by-step explanation:

divide 2 by 2/3

6 0
2 years ago
The length of the longest side of a triangle is 1 inch less than the sum of the lengths of the other two sides. How long is the
Gwar [14]
The length of the longest side is 17 inches.
4 0
3 years ago
The graph of f ′ (x), the derivative of f(x), is continuous for all x and consists of five line segments as shown below. Given f
Nataliya [291]

The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.

Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.

By the fundamental theorem of calculus,

\displaystyle f(5) = f(0) + \int_0^5 f'(x) \, dx

The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so

\displaystyle \int_0^5 f'(x) \, dx = \frac{5+2}2 \times 2 = 7

\implies \max\{f(x) \mid 0\le x \le5\} = f(5) = f(0) + 7 = \boxed{13}

8 0
2 years ago
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