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siniylev [52]
3 years ago
12

How do you graph y=2x+4 on a graph​

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

y =7 i think. idk im bad at math sorry. lol

You might be interested in
The RANGE of the function f is
monitta

Answer:

Step-by-step explanation:

The range of the function is what values of y from lowest to highest that are covered by the function.  The domain are the values on the left: A-E; the range are the values on the right: 1-3.  We state both domain and range in interval notation, stating only the lowest and highest values in either a set of brackets if the values are included, a set of parenthesis if the values are not included, or a mixture of both.  Our range is inclusive, so we mention the lowest and the highest only: [1, 3].

7 0
3 years ago
Pleaseeee helpppppppppp
o-na [289]

Answer:

25 ft^2

Step-by-step explanation:

In direct variation, if y varies directly with x, then the equation has the form

y = kx,

where k is the constant of proportionality. y is proportional to x.

Let's call the area y and the distance x.

Here, the area varies with the square of the distance, so the equation has the form

y = kx^2

Here, y is proportional to the square of x.

We can find the value of k by using the given information.

y = kx^2

When x = 20 ft, y = 16 ft^2.

16 = k(20^2)

k = 16/400

k = 1/25

The equation of the relation is:

y = (1/25)x^2

Now we use the equation we found to answer the question.

What is y (the area) when x (the distance) is 25 ft?

y = (1/25)x^2

y = (1/25)(25^2)

y = 25

Answer: 25 ft^2

5 0
2 years ago
Suppose a random sample of 50 college students are asked to measure the length of their right foot in centimeters. A 95% confide
hichkok12 [17]

Answer:

A  99% confidence interval  will be wider than a 95% confidence interval

Step-by-step explanation:

From the question we are told that

  The  95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm

Generally the width of a confidence interval is dependent on the margin of error.

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

From the above equation we see that

          E \ \  \alpha \ \   Z_{\frac{\alpha }{2} }

Here  Z_{\frac{\alpha }{2} }  is the critical value of the half of the level of significance and this value  increase as the confidence level increase

Now if a  99% confidence level is  used , it then means that the value of  

 Z_{\frac{\alpha }{2} }  will increase, this in turn will increase  the margin of error and in turn this will increase the width of the confidence interval

Hence a 99% confidence interval  will be wider than a 95% confidence interval

5 0
3 years ago
00:00
andreev551 [17]

Answer:

I need Help on this one too.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Pleased help me answer this I'm confused. look at picture​
skad [1K]

Answer:

23 + 16 = 39

39 - 16 = 23

the student did not reverse the sum correctly

7 0
3 years ago
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