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marysya [2.9K]
3 years ago
15

Calc Help Please!!! Urgent!!

Mathematics
1 answer:
tatyana61 [14]3 years ago
5 0

The derivative is just the slope.  So it's constant negative for the line up to x=-3.  Then we have a parabola that will go linearly from a positive slope to zero at the origin to a negative slope at x=3.  Then a constant positive slope.

So we're looking for flat negative line up to x=-3, linear starting positive and through the origin ending negative at x=3, then a flat positive.

Answer: third choice


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Systems of linear equations ; elimination method<br><br><br> pls help&lt;3
Basile [38]
<h3>Answer:</h3>

System

  • 10s +25t = 11700
  • s -2t = 0

Solution

  • s = 520
  • t = 260
<h3>Explanation:</h3>

Let s and t represent single-entry and three-day tickets, respectively. These variables represent the numbers we're asked to find: "how many of each [ticket type] he sold."

We are given the revenue from each ticket type, and the total revenue, so we can write an equation based on the relation between prices, numbers sold, and revenue:

... 10s +25t = 11700 . . . . . equation for total revenue

We are also given a relation between the two number of tickets sold:

... s = 2t . . . . . . . . . . . . . . . twice as many single tickets were sold as 3-day

We can rearrange this second equation to put it into standard form. That makes it easier to see what to do to eliminate a variable.

... s -2t = 0 . . . . . . . . . . . . subtract 2t to put into standard form

So, our system of equations is ...

  • 10s +25t = 11700
  • s -2t = 0

<em>What </em>elimination<em> is all about</em>

The idea with "elimination" is to find a multiple of one (or both) equations such that the coefficients of one of the variables are opposite. Then, the result of adding those multiples will be to eliminate that variable.

Here, we can multiply the second equation by -10 to make the coefficient of s be -10, the opposite of its value in the first equation. (We could also multiply the first equation by -0.1 to achieve the same result. This would result in a non-integer value for the coefficient of t, but the solution process would still work.)

Alternatively, we can multiply the first equation by 2 and the second equation by 25 to give two equations with 50t and -50t as the t-variable terms. These would cancel when added, so would eliminate the t variable. (It seems like more work to do that, so we'll choose the first option.)

<em>Solution by elimination</em>

... 10s +25t = 11700 . . . . our first equation

... -10s +20t = 0 . . . . . . . second equation of our system, multiplied by -10

... 45t = 11700 . . . . . . . . .the sum of these two equations (s-term eliminated)

... t = 11700/45 = 260 . . . . . divide by the coefficient of t

... s = 2t = 520 . . . . . . . . . . use the relationship with s to find s

_____

<em>Solution using your number sense</em>

As soon as you see there is a relation between single-day tickets and 3-day tickets, you can realize that all you need to do is bundle the tickets according to that relation, then find the number of bundles. Here, 2 single-day tickets and 1 three-day ticket will bundle to give a package worth 2×$10 + $25 = $45. Then the revenue of $11700 will be $11700/$45 = 260 packages of tickets. That amounts to 260 three-day tickets and 520 single-day tickets.

(You may notice that our elimination solution effectively computes this same result, where "t" and the number of "packages" is the same value (since there is 1 "t" in the package).)

6 0
3 years ago
BIG IDEAS MATH <br> help me out please hurry
arsen [322]
I will but the picture is blurry
5 0
3 years ago
Which equation is represented by the graph?
Scorpion4ik [409]
Answer: D, using rise over run the graph goes up 1 over 3 and the graph crosses the y-axis at -4 put that in y=mx+b and you get y=1/3x+-4
7 0
3 years ago
The probability of choosing a rotten apple from the bag of apples is Four-fifths. Which term best describes this probability? im
agasfer [191]
I think the answer is likely
5 0
3 years ago
Read 2 more answers
How do i solve divide 5/8 by 50%
Ede4ka [16]
50% is \frac{50}{100}
We have two ways to do this, pick your favor:
either by fractions:
\frac{5}{8} ÷ \frac{1}{2}
(\frac{50}{100} =  \frac{1}{2}
Multiply by the reciprocal of \frac{1}{2} which is 2(flip it)

\frac{5}{8} × 2 = \frac{5}{4} = 1.25

Or change them to decimals:
\frac{5}{8} = 0.625
\frac{50}{100} = 0.5

0.625 ÷ 0.5

0.5 I 0.625
multiply by 10 to make it easier to divide(it still gives us the same answer)
0.5 × 10 = 5
0.625 × 10 = 6.25
     1.25
5 I 6.25
    -5
     12
    -10
       25
      -25
         0

0.625 ÷ 0.5 = 1.25

7 0
2 years ago
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