Answer:
After 4 years, the value of the car would be of $5695.31.
Step-by-step explanation:
The formula for compound interest works perfectly in this case:
As in this case the repetitions per annum are just 1 (yearly), we can ignore the n.
Replacing variables with our values, a yields the depreciated value:
Answer: Nope, im currently doing well right now. Thank you though.
Step-by-step explanation:
136$
you find 20% of 170 by multiplying 0.2*170=34 then you’d subtract 170-34 to get 136
You can create two equations.
"<span>A car travels 20 mph slower in a bad rain storm than in sunny weather."
</span>
Where 'x' represents speed in sunny weather and 'y' represents speed in rainy weather.
"<span>The car travels the same distance in 2 hrs in sunny weather as it does in 3 hrs in rainy weather."
</span>Where 'x' represents speed in sunny weather and 'y' represents speed in rainy weather.
We want to find the speed of the car in sunny weather, or 'x'. Plug in the value for 'y' in the first equation into the second equation.
Distribute:
Subtract 3x to both sides:
Divide -1 to both sides:
So the car goes 60 mph in sunny weather.
There are 8 pints in one gallon. So, Avery would need 8 times 2 pints because she needs 2 gallons and there are 8 pints in every gallon.
8 x 2 = 16
Now subtract what she already has from the total she needs.
16 - 7 = 9
So, Avery needs 9 more pints of milk.
