What is a simple formula to solve a math sequence? Or a couple formulas if possible? Thanks!

1 answer:

7 0

2 normal types of sequences:

1. arythmetic sequences: each term is the same distance to the next term, example, 2,4,6,8, distance is 2

2. geometric sequences: the ratio of consecutive terms is the same, example: 2,4,8,16, ratio is 4:2=2:1, 2/1=2

the nth term is denoted by $a_{n}$
the first term is represented by $a_{1}$

for arythmetic sequences, the nth tem is
$a_{n}=a_{1}(n-1)d$ where d=distance between each term

for geometric sequences the nth term is
[tex] a_{n}=a_{1}r^{n-1} where r=ratio betwen consecutive terms

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How many quarters does Annie have A.35 B.49 C.3 D.7

spayn [35]

Answer: Annie has 49 Quarters

Explanation:
Sarah has 21 more quarters than Annie.
As shown, It says That Sarah has 28 quarters.
So, if Sarah has 21 more, it means you add 21 + 28
Resulting in 49.

Hope this helps you! If available please give me a Branliest. It is much appreciated!

- Mathhotdog •~•

6 0

2 years ago

Read 2 more answers

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

Answer:

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

Solution:

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago

Someone solve this for me please: Find a vector v such that || v || = 10 and v is in same direction as 2i + 3j

drek231 [11]

Answer:

Step-by-step explanation:

$\overrightarrow{a}=2*\overrightarrow{i}+3*\overrightarrow{j}\\\\||\overrightarrow{a}||=\sqrt{2^2+3^2} =\sqrt{13} \\\\\boxed{\overrightarrow{v}=\dfrac{20}{\sqrt{13}}*\overrightarrow{i}+\dfrac{30}{\sqrt{13}}*\overrightarrow{j}} \\\\\\||\overrightarrow{a}||=\sqrt{(\dfrac{20}{\sqrt{13}})^2+(\dfrac{30}{\sqrt{13}})^2} =\sqrt{\dfrac{400+900}{13} }==\sqrt{\dfrac{1300}{13} }=\sqrt{100}=10 \\$