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s344n2d4d5 [400]
3 years ago
8

A summer camp is organizing a hike and needs to buy granola bars for the campers. The granola bars come in small boxes and large

boxes. Each small box has 12 granola bars and each large box has 30 granola bars. How many granola bars are there in 8 small boxes and 7 large boxes? How many granola bars are there in ss small boxes and ll large boxes?
8 small boxes and 7 large boxes:
s small boxes and ll large boxes:
Mathematics
1 answer:
pychu [463]3 years ago
8 0

Answer: 306

Step-by-step explanation:

You might be interested in
Write 21/7 as a whole number
Sunny_sXe [5.5K]

Answer: 3

Step-by-step explanation:

7x=21 21/7=3

7 0
4 years ago
How many 1/2 go in 3/4<br> How many 1/2 go in to 1/4
dedylja [7]

Answer:

1, 0 or 1, 1/2

Step-by-step explanation:

\frac{1}{2} = \frac{2}{4}

2 goes into 3 once

and doesn't fit into 1

So, \frac{2}{4} goes into \frac{3}{4} once

and it doesn't go into \frac{1}{4}

It could also be 1, 1/2

because half of two can fit into 1

so half of \frac{2}{4} can go into \frac{1}{4}

I don't know which one you're looking for...

Sorry

4 0
3 years ago
A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili
Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

18x = 3*31

x = \frac{31*3}{18}

x = 5.17

So \mu = 5.17

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

So

P(X \leq 3) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X \leq 3)

In which

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057

P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294

P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760

P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309

So

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242

Finally

P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

8 0
4 years ago
Find the rule. Solve for n. Answer quick please :)
defon

Answer:

9

Step-by-step explanation:

6 0
3 years ago
A survey was taken of 2000 voters before an election.1650 of the ones surveyed said they would vote for candidate A.What percent
antiseptic1488 [7]
Total of 2000 voters......1650 said they would vote for candidate A

the percent who voted for candidate A is : 1650/2000 = 0.825
multiply that by 100 to get ur percent....0.825 * 100 = 82.5% <==
6 0
3 years ago
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