Call : x - 4y + z = 6 (e1) == > z = 6 - x + 4y 2x + 5y - z = 7 (e2) 2x - y - z = 1 (e3)
sub z from e1 in e2 you have : 2x + 5y - 6 + x - 4y = 7 ==> 3x + y = 13 ==> 3x = 13 - y (*)sub z from e1 in e3 you have: 2x - y - 6 + x - 4y = 1 ==> 3x - 5y = 7 (**)
sub 3x from (*) in (**), you have 13 - y - 5y = 7 ==> 6 = 6y ==> y = 1sub y = 1 into (*), you have: 3x = 13 - 1 = 12 ==> x = 4
sub both y = 1 and x = 4 into (e1), you have: 4 - 4(1) + z = 6 ==> z = 6
so answer : x = 4, y = 1, z =6 (you can use these values to check other equations to see if they come out all right)
This is the image the points form, if you know your quadrilaterals, this should make it easier to picture and label. Need any further explanation?
Answer:
B. Isosceles
Step-by-step explanation:
at the first appearance, it looks to be equilateral but it's not.
