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Feliz [49]
3 years ago
7

number 4 I have absolutely no idea how to do. I generally understand finding distance on the coordinate plane but this has reall

y confused me. Please help.

Mathematics
1 answer:
Over [174]3 years ago
3 0
For Part A, in creating the square, you did it correctly.

Now for Part B, you can create a right triangle by adding a point at -4, -3, and we'll call it, say, T.

Then you can use the Pythagorean's Theorem to find the length of one side of the square.

The Pythagorean's Theorem is a^{2} +  b^{2} = c^{2}

A would be the distance between P and T, and B would be the distance between Q and T. So then, a would be 7, and B would be 2. 

To fill it in, it would be 7^{2} +  2^{2} = c^{2}

or 49 + 4 = c^{2}

or 53 = c^{2}

or \sqrt{53} = x

Which is equal to about 7.28

Now multiply that by 4 to get the perimeter, or 29.12

So the perimeter would be about 29.12


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the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
2 years ago
A 5x5 table is filled with numbers (one number per cell). It is known that the product of 5 numbers in each column is negative.
Advocard [28]

Answer:

Yes

Step-by-step explanation:

A negative multiplied by another negative will turn into a positive. A positive multipled by a negative will stay as a negative.

5 0
2 years ago
Find the amount in a continuously compiunded account for the following condition. Principal, $4000; Annual interest rate, 5.1%;
Ket [755]
A = P*e^(rt)

Here,

A = $4000*e^(0.051*2) = $4000*e^1.02 = $4000(2.773) = $11092.78 

Note:  This seems very high to me.
7 0
3 years ago
The square ABCD is divided into eight equal parts. The shaded area is 25 cm². What is the area of the square ABCD​
Akimi4 [234]

Answer:

I think the answer is 200cm^2

Step-by-step explanation:

since the square is divided into eight equal parts

and one shaded part is =25cm^2

multiply the area of the shaded part by the number of equal parts

= 25cm^2 ×8

= 200cm^2

6 0
3 years ago
How do I add this fraction 7 9/12 + 4 5/9
vovangra [49]
Make the same denominator (12) and then make them both non mixed numbers 93/12 and 54.6666.../12

so 147.666.../12

12.305/12
7 0
3 years ago
Read 2 more answers
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