Question

number 4 I have absolutely no idea how to do. I generally understand finding distance on the coordinate plane but this has really confused me. Please help.

Answer 1

For Part A, in creating the square, you did it correctly.

Now for Part B, you can create a right triangle by adding a point at -4, -3, and we'll call it, say, T.

Then you can use the Pythagorean's Theorem to find the length of one side of the square.

The Pythagorean's Theorem is $a^{2} + b^{2} = c^{2}$

A would be the distance between P and T, and B would be the distance between Q and T. So then, a would be 7, and B would be 2. 

To fill it in, it would be $7^{2} + 2^{2} = c^{2}$

or 49 + 4 = $c^{2}$

or 53 = $c^{2}$

or $\sqrt{53}$ = x

Which is equal to about 7.28

Now multiply that by 4 to get the perimeter, or 29.12

So the perimeter would be about 29.12