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3 years ago

SMART STUDENT PLEASE NEED GOOD MATH STUDENT

Mathematics

1 answer:

tangare [24]3 years ago

8 0

Answer:

Therefore 'x' is equal to 65.4°

Step-by-step explanation:

In Right Angle Triangle ABC

∠ B = 90°

AC = Hypotenuse = 12

CB = Adjacent Side = 5

To Find:

∠ C = x

Solution:

In Right Angle Triangle ABC Cosine Identity we have

$\cos C = \frac{\textrm{side adjacent to angle C}}{Hypotenuse}\\$

Substituting the values we get

$\cos C = \dfrac{CB}{AC}=\dfrac{5}{12}$

$\angle C = \cos^{-1}(0.4166)=65.37=65.4\°$

Therefore 'x' is equal to 65.4°

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What number is 35 percent of 120

KIM [24]

What you would do is multiply for this problem.
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2 years ago

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Given the equation Y -3 equals 1/2 (X +6 )in point slope form identify the equation of the same line in standard form

liberstina [14]

The standard form of a line:

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3 years ago

What is the image of (-1,0) after a reflection over the line y = -x?

umka2103 [35]

Answer:

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2 years ago

F(x) = 7|x| awnser the question for some points

Eddi Din [679]

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2 years ago

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Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and

Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling:

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437$

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$P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)$

Calculation the value from standard normal z table, we have,

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0.918 is the probability that the sample average sediment density is at most 3.00

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3 years ago

SMART STUDENT PLEASE NEED GOOD MATH STUDENT​

SMART STUDENT PLEASE NEED GOOD MATH STUDENT