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saw5 [17]
4 years ago
14

99 points ALGERBA 1 HELLP

Mathematics
1 answer:
zavuch27 [327]4 years ago
7 0
PART A

The given equation is 3(2)^{x}

When x=1, h(1)=3 (2)^{1}=6
When x=2, h(2)=3 (2)^{2}= 12
When x=3, h(3)=3 (2)^{3} = 24
When x=4, h(4)=3 (2)^{4}=48

Between x=1 and x=2 there is an increase by 12
Between x=3 and x=4 there is an increase by 24

PART B

The change in section B is twice the change in section A. This change is an exponential change indicated by the expression 2^{x} in the function. If we continue to check the rate of change between x=5 and x=6, we will discover that the change will be four times the rate of change between x=3 and x=4. 
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