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2 years ago

Please help!!!!!!!!!!!!!

Mathematics

1 answer:

vampirchik [111]2 years ago

6 0

Plumber a = 60x
Plumber b = 40+55x
An 8 hour job would cost the same for both plumbers. It would cost $480. Plumber a should be hired for a 5 hour job.

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How is an equation like a balance scale!?! please make the response short and easy to understand !!

Sauron [17]

You have to equal out each side to fine the value of the variable.

hope this helped!!!
can u mark me brainliest plz?

5 0

3 years ago

Given that u = 2.89 and v = 5.7, find the value of G when:<br> a G = 5u + 2y

EleoNora [17]

Answer:

28.85

Step-by-step explanation:

Plug the values in and solve.

G = 5u + 2y

G = 5(2.89) + 2(5.7)

G = 14.45 + 11.4

G = 25.85

5 0

2 years ago

Find the slope of the line that passes through the following points: (5, 3) and (-2, -4)

Aleksandr [31]

Answer:

Step-by-step explanation:

To find the slope, you must subtract the second y axis from the first y axis then the second x axis from the first x axis.

Problem: (5, 3) (-2, -4)

Solution: Step 1. - 4 - 3 = 7 (subtract the second y axis from the first y axis)

Step 2. - 2 - 5 = 7 (subtract the second x axis from the first x axis)

Answer: 7/7

Final Answer: 1

Mark me as brainliest!!

6 0

2 years ago

From a standard deck of 52 cards, what is the probability of picking a King at random from the deck?

MaRussiya [10]

Answer:

1/13

Step-by-step explanation:

there are 4 kinds and 52 cards so its 4/52 which simplifies to 1/13

7 0

2 years ago

Read 2 more answers

Solve 0 = (x – 4)2 – 1 by graphing the related function.

fomenos

Answer:

Therefore, the solutions of the quadratic equations are:

$x=5,\:x=3$

The graph is also attached.

Step-by-step explanation:

The solution of the graph could be obtained by finding the x-intercept.

$y=\left(x-\:4\right)^2-1$

Finding the x-intercept by substituting the value y = 0

$y=\left(x-\:4\right)^2-1$

$\:0\:=\:\left(x\:-\:4\right)^2\:-\:1$ ∵ y = 0

$\left(x-4\right)^2-1=0$

$\left(x-4\right)^2-1+1=0+1$

$\left(x-4\right)^2=1$

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$\mathrm{Solve\:}\:x-4=\sqrt{1}$

$\mathrm{Apply\:rule}\:\sqrt{1}=1$

$x-4=1$

$x=5$

$\mathrm{Solve\:}\:x-4=-\sqrt{1}$

$\mathrm{Apply\:rule}\:\sqrt{1}=1$

$x-4=-1$

$x=3$

So, when y = 0, then x values are 3, and 5.

Therefore, the solutions of the quadratic equations are:

$x=5,\:x=3$

The graph is also attached. As the graph is a Parabola. It is visible from the graph that the values of y = 0 at x = 5 and x = 3. As the graph is a Parabola.

8 0

3 years ago