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Katena32 [7]
3 years ago
9

Write an equation of the line that passes through (2, -3) and is perpendicular to the line y=-2x-3

Mathematics
2 answers:
Natalija [7]3 years ago
8 0

Answer:

y=\frac{1}{2} (x-2)-3 or y=\frac{1}{2} x-4

Step-by-step explanation:

The perpendicular slope is the opposite-reciprocal of the original slope:

Perpendicular slope of -2 is \frac{1}{2}

Write the equation in point-slope form (y=a(x-h)+k):

y=\frac{1}{2} (x-2)-3

Convert to slope-intercept form if needed:

y=\frac{1}{2} x-1-3

y=\frac{1}{2} x-4

Ulleksa [173]3 years ago
8 0
Im only commenting so you can make the answer above the brainliest!
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Will give brainliest if done properly
k0ka [10]

Answer:

\sf  \boxed{  \sf y - 3 = \dfrac{3}{2} (x - 6)}

Explanation:

\sf Given \ equation: y = \dfrac{3}{2} x - 5

Comparing it with slope intercept form "y = mx + b" where 'm' is slope and 'b' is y-intercept.

Here slope: 3/2 and y-intercept: -5

Parallel slope has the same tangent slope.

Pass through point (x, y) = (6, 3)

Equation:

\sf y - y_1 = m(x  - x_1)

\rightarrow \sf y - 3 = \dfrac{3}{2} (x - 6)

6 0
1 year ago
Translations Use the translation (x,y)(x+5,y-9) for questions 1-7. 1. What is the image of A(-1,3)? 2. What is the image of B(2,
lara [203]

Answer:

The answer is c hopes this helps

7 0
2 years ago
Daniel bought 3 sweaters that each cost the same amount and a jacket that cost $40. The items he bought cost a total of $100 bef
MA_775_DIABLO [31]
3x+40=100


subtract 40 from both sides

3x= 60

divide by 3

x=20
each Sweater cost 20
3 0
2 years ago
Searching for the Brainliest answers for this question!
vaieri [72.5K]
C because if the line Q is 1,5 and 1,8, it would have to be a vertical line, as the X axis doesn’t change. As i know, a vertical line always has a slope of 0, and a horizontal line (which the x-axis is) always has an undefined slope.
3 0
3 years ago
Read 2 more answers
What is the true solution to In 20+ In 5= 2 In x?<br> x=5. A<br> X= 10 b<br> X=50 c<br> X= 100 d
lions [1.4K]

ln(20) + ln(5) = 2 ln(<em>x</em>)

ln(20×5) = ln(<em>x</em> ²)

ln(100) = ln(<em>x</em> ²)

100 = <em>x</em> ²

<em>x</em> = 10

4 0
3 years ago
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