Answer:
D. m<RST = 2(m<TSU)
Step-by-step explanation:
Given that m<RST = 76°, m<RSU = 48°, and m<TSU = 38°, this implies that:
SU is an angle bisector of angle RST. Thus,
m<RST is twice the measure of <RSU or <TSU.
Therefore, the only option that is correct is:
D. m<RST = 2(m<TSU)
Answer:
1 hundreths is 10 times greater than 1 thousandths.
Step-by-step explanation:
just like 100 is ten times greater than 10.
Y = mx + b. Use this equation for most linear functions. Enter the information that is given to you.

Multiply the -3 and 4 to get 12.

Now divide the -12 from both sides.

-12 cancels out on the right side and your left with

Now re-enter the info back into the formula.

Then you've got your formula
U have a geometric sequence. To find the common ratio, divide the second term by the first term. 6/12 = 1/2
an = a1 * r^(n-1)
n = term to find = 10
a1 = first term = 12
r = common ratio = 1/2
now we sub
a(10) = 12 * 1/2(10 - 1)
a(10) = 12 * 1/2^9
a(10) = 12 * 1/512
a(10) = 12/512 reduces to 3/128 ,<== ur 10th term
the answer would be B because if you imput the variables the equation comes out equal.