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4 years ago

Does the addition problem show a way to add 27 + 38?

Mathematics

1 answer:

Dmitry [639]4 years ago

8 0

Answer:

a. yes

b. no

c. yes

d. yes

Step-by-step explanation:

For a, 27 + 38 can be broken apart. 27 is broken up by adding smaller numbers (20 + 7 = 27) and the same is done with 38 (30 + 8 = 38), so A and C shows a way to add 27 and 38. In C, the numbers are just put into a different order. B is not a way to add 27 and 38, because the sum is different.

27 + 38 = 65, however 20 + 70 + 38 = 128. The addition problem for D is a way to solve for 27 + 38, because it is broken up differently than A and C. They instead added the 20 and 30 together first, then split up 15 (from 8+7) into 10 and 5. So D is a way to solve, because it gets the same answer as 27 and 38 :D

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Answer:

60,480 is the correct answer.

Step-by-step explanation:

First of all, let us have a look at the formula of factorial of a number 'n':

$n! = n \times (n-1) \times (n-2) \times ...... \times 1$

i.e. multiply n with (n-1) then by (n-2) upto 1.

Keep on subtracting 1 from the number and keep on multiplying until we reach to 1.

So, $9!$ can be written as: $9 \times 8 \times 7 \times ...... \times 1$

Similarly $3!$ can be written as: $3 \times 2 \times 1$

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$9 \times 8 \times 7 \times ...... 3 \times 2 \times 1\\\Rightarrow 9 \times 8 \times 7 \times ...... 3 !$

Now, the expression to be evaluated:

$\dfrac{9!}{3!} = \dfrac{9 \times 8 \times 7 \times ..... \times 3!}{3!}\\\Rightarrow 9 \times 8 \times 7 \times 6 \times 5 \times 4\\\Rightarrow 60480$

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Answer:

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

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