Question

What is the equation of the line, in slope-intercept form, that contains the points (−1, 2) and (2, −1)?

Answer 1

(-1,2)(2,-1)
slope = (-1 - 2) / (2 - (-1) = -3/3 = -1

y = mx + b
slope(m) = -1
use either of ur points...(-1,2)...x = -1 and y = 2
sub and find b, the y int
2 = -1(-1) + b
2 = 1 + b
2 - 1 = b
1 = b

so ur equation is : y = -x + 1 <==