Answer:
The wall is 90 meters wide.
Step-by-step explanation:
1. set up and solve a proportion to find the value of w like this:
1cm=6cm
15m=wm
2. cancel out the like units on both sides of the equation
1=6
15=w
3. Equate the cross products, and then solve for w:
1*w=15*6
w=90 The actual width of the wall is 90 meters.
G(x) = (x+4)^4 is the answer. It's D. last choice
G(x) = (x+4)^4 shifted F(x) = x^4 4 units to the left
Answer:
The total length of fencing needed to enclose the kennel 74 feet.
Step-by-step explanation:
Given:
The blueprint of the rectangular kennel shows one side is 23 feet and another side is 14 feet.
As it is a rectangular shape, let the two sides be the length and the breadth of the rectangular kennel. i.e
![length = L = 23\ feet\\breadth = B = 14\ feet\\](https://tex.z-dn.net/?f=length%20%3D%20L%20%3D%2023%5C%20feet%5C%5Cbreadth%20%3D%20B%20%3D%2014%5C%20feet%5C%5C)
To find:
Total length of fencing needed is to enclose the kennel. i.e
Perimeter of a rectangular kennel = ?
Solution:
we have the formula for perimeter of a rectangle as giving below.
![\textrm{perimeter of rectangle} = 2(length + breadth) \\\textrm{total length of fencing} = 2( L+B)\\ \textrm{substituting the values of length and breadth we get}\\ \textrm{total length of fencing} = 2(23+14)\\=2\times37\\= 74\ feet](https://tex.z-dn.net/?f=%5Ctextrm%7Bperimeter%20of%20rectangle%7D%20%3D%202%28length%20%2B%20breadth%29%20%5C%5C%5Ctextrm%7Btotal%20length%20of%20fencing%7D%20%3D%202%28%20L%2BB%29%5C%5C%20%5Ctextrm%7Bsubstituting%20the%20values%20of%20length%20and%20breadth%20we%20get%7D%5C%5C%20%5Ctextrm%7Btotal%20length%20of%20fencing%7D%20%3D%202%2823%2B14%29%5C%5C%3D2%5Ctimes37%5C%5C%3D%2074%5C%20feet)
Therefore,the total length of fencing needed to enclose the kennel 74 feet.
We have that
y< 6x-3
using a graph tool
see the attached figure
the answer in the attached figure
Answer:
Approximately 775,000.
Step-by-step explanation:
The number is almost in between 750,000 and 800,000. The number in the middle of these two is 775,000.