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3 years ago

Fred Flintstone bought seven boxes to put with his collection of boxes. A week

Mathematics

2 answers:

Helga [31]3 years ago

8 0

Answer:

I think the right answer is 37.

klio [65]3 years ago

7 0

Answer:

Step-by-step explanation:

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Math 7. Grade 7.

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Which of the following points might be on the graph of f(x)

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Where’s the equation

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The height of a door would be about A: 8 inches B: 8 feet C: 8 yards D: 8Miles

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8 inches :) (im pretty sure)

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The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the

yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0

3 years ago

The lengths of two sides of a right triangle are 5 inches and 8 inches. What is the difference between the two possible

3241004551 [841]

Answer:

Option 2 - 3.2 inches.

Step-by-step explanation:

Given : The lengths of two sides of a right triangle are 5 inches and 8 inches.

To find : What is the difference between the two possible lengths of the third side of the triangle?

Solution :

According to question, it is a right angle triangle

Applying Pythagoras theorem,

$H^2=P^2+B^2$

Where, H is the hypotenuse the longer side of the triangle

P is the perpendicular

B is the base

Assume that H=8 inches and B = 5 inches

Substitute the value in the formula,

$8^2=P^2+5^2$

$64=P^2+25$

$P^2=64-25$

$P^2=39$

$P=\sqrt{39}$

$P=6.24$

Assume that P=8 inches and B = 5 inches

Substitute the value in the formula,

$H^2=8^2+5^2$

$H^2=64+25$

$H^2=89$

$H=\sqrt{89}$

$H=9.43$

Therefore, The possible length of the third side of the triangle is

$L=H-P$

$L=9.43-6.24$

$L=3.19$

Therefore, The difference between the two possible lengths of the third side of the triangle is 3.2 inches.

So, Option 2 is correct.

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3 years ago

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