Non-random mating is assortative mating. It is a pattern and form of sexual selection in which individuals with similar phenotypes mate with one another more frequently than would be expected under a random mating pattern. non-random mating can act as an ancillary process for natural selection to cause evolution to occur. It’s also bad for evolution because any departure from random mating upsets the equilibrium distribution of genotypes in a population. Recombination is a process by which pieces of DNA are broken and recombined to produce new combinations of alleles. recombination is important to somatic cells in eukaryotes because it can be used to help repair broken DNA. recombination by itself does not cause evolution to occur. Rather, it is a contributing mechanism that works with natural selection by creating combinations of genes that nature selects for or against. Non-random mating affects the evolution more than recombination
If you eat unhealthy now then you could develop health issues such as diabetes heart problems wating disorders and cause obesity if you eat unhealthy then you probably won't live as long of a life as compared to someone who has been eating healthy and the if you eat good now you can love a longer life with less problems
Anaphylaxis,<span>serum sickness and toxicity from food are the three problems.
Anaphylaxis refers to a severe and very serious allergic reaction which should be treated right away otherwise it may caus death, Serum sickness is also similar to the allergy and in type II hypersensitivity and clinically we can say that the reaction due to the medicine that does not contain protein. Toxicity from food refers to the food poisoning that is caused by contaminated food.</span>
Answer:
The process that is used to describe this is C. Replication
Explanation:
This model has been developed and worked by many people long ago who were all interested in looking how DNA is the genetic blueprint by which the organism is made up.
4.) We are told that ball A is travelling from right to left, which we will refer to as a positive direction, making the initial velocity of ball A, +3 m/s. If ball B is travelling in the opposite direction to A, it will be travelling at -3 m/s. The final velocity of A is +2 m/s. Using the elastic collision equation, which uses the conservation of linear momentum, we can solve for the final velocity of B.
MaVai + MbVbi = MaVaf + MbVbf
Ma = 10 kg and Mb = 5 kg are the masses of balls A and B.
Vai = +3 m/s and Vbi = -3 m/s are the initial velocities.
Vaf = +2 m/s and Vbf = ? are the final velocities.
(10)(3) + (5)(-3) = (10)(2) + 5Vbf
30 - 15 = 20 + 5Vbf
15 = 20 + 5Vbf
-5 = 5 Vbf
Vbf = -1 m/s
The final velocity of ball B is -1 m/s.
5.) We are now told that Ma = Mb, but Vai = 2Vbi
We can use another formula to look at this mathematically.
Vaf = [(Ma - Mb)/(Ma + Mb)]Vai + [(2Mb/(Ma + Mb)]Vbi
Since Ma = Mb we can simplify this formula.
Vaf = [(0)/2Ma]Vai + [2Ma/2Ma]Vbi
Vaf = Vbi
Vbf = [(2Ma/(Ma + Mb)]Vai + [(Ma - Mb)/(Ma + Mb)]Vbi
Vbf = [2Mb/2Mb]Vai + [(0)/2Mb]Vbi
Vbf = Vai
Vaf = Vbi
Vbf = 2Vbi
If the initial velocity of A is twice the initial velocity of B, then the final velocity of A will be equal to the initial velocity of B.
If the initial velocity of A is twice the initial velocity of B, then the final velocity of B will be twice the initial velocity of B.
