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vichka [17]
3 years ago
5

Wat is 1000 divided by 350

Mathematics
1 answer:
pochemuha3 years ago
7 0
2.8571 i think im not sure
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A triangle has vertices at (4,3), (-2,4), and (-4, 2). What are the coordinates of the vertices of the image
Alexeev081 [22]

The coordinates are (4,3) ►(6,-2)

(-4,2) ►(-2,-3)

. (-2,4) →(0,-1)

8 0
3 years ago
Read 2 more answers
Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4
vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

c^2 = 4^2 + 6^2

c^2 = 16 + 36

c^{2} = 52

Pythagoras' theorem for the middle one :

b^{2} = 6^{2} + a^{2}

Pythagoras' theorem for the biggest one :

(4+a)^2 = c^2 + b^2

16 + 8a + a^2 = 52 + b^2

Using the formula before (for b^2) it becomes :

16 + 8a + a^2 = 52 + (6^2 + a^2)

16 + 8a + a^2 = 52 + 6^2 + a^2

16 + 8a = 52 + 6^2

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

a = \frac{72}{8}

a = 9

Verifying :

b^2 = 6^2 + a^2

b^2 = 36 + 81

b^2 = 117

b^{2} = 117

The biggest one :

(4+a)^2 = c^2 + b^2

(4+9)^2 = 52 + 117

13^2 = 169

True

8 0
2 years ago
From the top of a mountain to the floor of the valley below is 5,192 feet. If the valley is 108 feet below sea level, what is th
aniked [119]

Answ5184

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Jesse made a model of a mountain range for class. to do this, he bought a cylinder of cardboard and cut it into three cones. eac
aniked [119]
By definition, the volume of the cone is given by:
 V = (1/3) (π) (r ^ 2) (h)
 Substituting values we have:
 V = (1/3) (π) ((4/2) ^ 2) (5)
 V = (20/3) (π)
 Then, the volume of the cylinder is:
 Vc = 3 * V
 Vc = 3 * (20/3) (π)
 Vc = 20π
 Answer:
 
the volume of the original cylinder jesse bought is:
 
Vc = 20π
4 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation y=-16x^2+224x+121. We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute y=0 in our given equation as:

0=-16x^2+224x+121

Let us solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}

x=\frac{-224\pm\sqrt{50176+7744}}{-32}

x=\frac{-224\pm\sqrt{57920}}{-32}

x=\frac{-224\pm240.66574}{-32}

x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}

x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}

x=-0.520804375, x=14.520804375

Upon rounding to nearest 100th of second, we will get:

x\approx -0.52, x\approx 14.52

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

6 0
3 years ago
Read 2 more answers
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