I only have the answer to one sorry

If we want to find the distance between two points in a coordinate plane we use a different formula that is based on the Pythagorean Theorem were (x1,y1) and (x2,y2) are the coordinates and d marks the distance

im not sure this is right

6 0

3 years ago

Read 2 more answers

two lines a and b are perpendicular. line a has equation 3y-2x+2=0 and meets line b at the point(4,7). find the equation of line

valkas [14]

Answer:

Step-by-step explanation:

3y - 2x +2 = 0

3y = 2x - 2

$y = \dfrac{2}{3}x-\dfrac{2}{3}$

y = mx + b

Slope of line a = 2/3

Product of slope of perpendicular line = -1

$Slope \ of \ line \ b = \dfrac{-1}{\dfrac{2}{3}}=\dfrac{-3}{2}$

Equation of line b:

$y=\dfrac{-3}{2}x+b$

Line b passes through (4,7)

$7 = \dfrac{-3}{2}*4+b\\\\\\7= -6 + b\\\\b = 7 + 6\\\\b = 13$

Equation of line b:

$y=\dfrac{-3}{2}x+13$

Multiply the equation by 2

2y = -3x + 26

3x + 2y - 26 = 0

3 0

3 years ago

You might need:

jonny [76]

The answer is 37, you add up all the numbers and divide whatever number you got by the amount of numbers there are :)

8 0

3 years ago

A leprechaun places a magic penny under a girl's pillow. The next night there are 2 magic pennies under her pillow. The followi

vfiekz [6]

Answer:

Step-by-step explanation:

Since the pennies need to be kept under the pillow in order to be doubled, we're really looking for the day the girl will wake up with 5 billion pennies under her pillow.

The general formula of that geometric sequence will be: t = 1 + 2^(n-1)

We need to find the value of n when t will be over 5,000,000,000.

So, the equation becomes:

5,000,000,001 = 1 + 2^(n-1)

$2^{n-1}= 5,000,000,001$

$log(2^{n-1}) = log(5,000,000,000)$

(n-1) * log(2) = log(5,000,000,000)

n-1 = log(5,000,000,000) / log(2)

n-1 = 22.25

n = 33.25

Since it has to be complete days, and we have to reach over 5 billion, then we round it up to 34.

7 0

3 years ago