The circumference of the outer edge of the path around the pool is 113.04 ft.
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What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
To know more about circumference click the link given below.
brainly.com/question/5023328
16 because the legth of TQ is the same as SR I hope thats right i checked with a ruler. :)
Answer:
1. Undefined
2. Negative
3. Zero
4. Positive
Step-by-step explanation:
1. Undefined, the line moves in both directions vertically. It's impossible to tell what the slope is.
2. Negative, the line is decreasing at a constant rate, the slope is negative.
3. Zero, the line doesn't increase or decrease, therefore the slope is 0. (No changes)
4. Positive, the line is increasing at a large rate, the slope is positive.
Answer:
$64
Step-by-step explanation:
Since there were 4 of them and the coupons were $10 off, they saved a total of $40
To find how much they would have spent without the coupons, add 40 to 216:
216 + 40
= 256
To find the normal cost of one ticket, divide this by 4:
256/4
= 64
So, the price of one concert ticket without the coupon is $64