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Artist 52 [7]
3 years ago
5

I need help with this please

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

Not a function because there are two values of y for x = -8.

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The atmospheric pressure P on a balloon or in aircraft decreases with increasing height . This pressure measured in Millimeters
Vesnalui [34]

Answer:

(A)   5.47 km

(B)   1.38 km

Step-by-step explanation:

The relationship between Pressure (mmHg) and Height (km) is given by the equation below:

p =760 e⁻ 0.145h----------------------------------------------------- (1)

(a) The height of the aircraft can be calculated by making 'h' the subject of equation (1)

In (p/760) = -0.145 h

h = -In (p/760) /0.145

h= In (760/p)/ 0.145------------------------------------------------- (2)

For the aircraft, p =344 mmHg; substituting into (2)

h = In (760/344)/0.145

   = 0.7926/0.145

   = 5.4662 km

   ≈ 5.47 km

(b) p= 622 mmHg at the mountain top. Substituting into equation  (2) we have:

h = In (760/622)/0.145

  = 0.2003 / 0.145

  =  1.3813 km

  ≈  1.38 km

4 0
3 years ago
To determine whether 30 horses can be put into 7 stalls; so that in every stall there may be, either a single horse, or an odd n
algol [13]

Answer: No solutions

If i put any combo of horses of single or odd, always an even number at last stall.

3 0
3 years ago
PLS HELP (IN CLASS)!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! WHAT IS THE ANGLE OF C
borishaifa [10]

Answer:

50 :D

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
You can win concert tickets from a radio station if you are the first person to call when the song of the day is played, or if y
Anit [1.1K]

The song of the day is announced at a random time between 7:00 and 7:30, so you have a 30-minutes span of time where the song could be announced. If you start listening to the radio 20 minutes in, you're at 2/3 of the time. So, there is a 2/3 chance that the song has already been chosen, and a 1/3 chance that it will be announced in the remaining 10 minutes.

Similarly, the trivia question is asked at a random time between 7:15 and 7:45 so there is again a 30-minutes span of time. But this time, we're only 5 minutes late, so there is a 5/30=1/6 chance that the question was already asked, and a 25/30=5/6 chance that the question will be asked in the remaining 25 minutes.

So, there are four scenarios:

  • You have missed both the song of the day and the trivia question. Given all we said, this event has a chance of

\dfrac{2}{3}\cdot\dfrac{1}{6} =\dfrac{2}{18}

  • You miss the song, but not the trivia:

\dfrac{2}{3}\cdot\dfrac{5}{6} =\dfrac{10}{18}

  • You miss the trivia, but not the song

\dfrac{1}{3}\cdot\dfrac{1}{6} =\dfrac{1}{18}

  • You don't miss anything:

\dfrac{1}{3}\cdot\dfrac{5}{6} =\dfrac{5}{18}

You're interested in the probability of missing either of the announcements, so you want to sum the two middle cases (in the first you miss everything, in the second you don't miss anything).

Your result is thus

\dfrac{10}{18}+\dfrac{1}{18} = \dfrac{11}{18}

3 0
3 years ago
PLS HElp PLZZZZZZZZZZZZZZZZZZZ
natali 33 [55]

Answer:

c

Step-by-step explanation:

they use multiples of 9

4 0
3 years ago
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