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3 years ago

How do you solve 3x-15=7x-10

Mathematics

2 answers:

Anna35 [415]3 years ago

8 0

Answer:

I think it’s -1.25???? Idk I’m too lazy to check my math

Step-by-step explanation:

You take the 3x and subtract it from both sides. You now have -15 = 4x -10

Then you do +10 to both sides. Now you have -5 = 4x

Divide each side by 4 and you have -1.25 = x

Now check your math.

3 • -1.25 -15 = 7 • -1.25 -10

Fofino [41]3 years ago

5 0

Answer:

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form: x=-45

−

Decimal Form:x=-1.25

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1.25

Mixed Number Form:x=-14

−

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3 years ago

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3 years ago

Read 2 more answers

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ICE Princess25 [194]

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4 years ago

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What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

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4 years ago