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3 years ago

11

What is the equation of a line with slope −23 and a y-intercept of −4 ?

1 answer:

Alona [7]3 years ago

8 0

Answer:

its A

Step-by-step explanation:

the y intercept would be -4 and the slope would be -23, put it in y=mx+b form

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Find the interval(s) of upward concavity on this accumulation function.

maxonik [38]

$\displaystylef(x)=\int_{0}^{x^2}\sec^2(\sqrt{x})dx \\=\int_{0}^{\sqrt{x^2}}\sec^2(u)\cdot2udu \\=2\int_{0}^{\sqrt{x^2}}\sec^2(u)du \\=2\Big[u\tan(u)-\int\tan(u)du\Big]_{0}^{\sqrt{x^2}} \\=2\Big[u\tan(u)+\ln\Big(\mathrm{abs}(\cos(u))\Big)\Big]_0^x \\=2\Big(x\tan(x)+\dfrac{1}{2}\ln\Big(\cos^2(x)\Big)\Big) \\=2x\tan(x)+\ln(\cos^2(x))$

Hope this helps.

6 0

3 years ago

What is -(1)<br>Please help me.

KatRina [158]

It Is Just -1.
The Parenthesis Are All Simplified, And The Subtraction Sign Changes It To Negative. So, 1 Changed To Negative Is -1. <span />

8 0

3 years ago

A = bh/2 solve for b

rjkz [21]

$A = \dfrac{bh}{2}$

Cross multiply:
$2A = bh$

Divide by h on both sides:
$b = \dfrac{2A}{h}$

8 0

3 years ago

What are the solutions for x when y is equal to 0 in the following quadratic

Scrat [10]

Answer: Option C

Step-by-step explanation:

Given the quadratic equation $y = x^2 - 13x$ , substitute $y=0$ :

$0 = x^2 - 13x$

In this case, to find the solutions of the given quadratic equation, you must factor out the variable "x". Then:

$0=x(x-13)$

Therefore, you get that the solutions of this equation are the following:

$x=0\\\\\\x-13=0\\x=13$

Then, the answer is:

$x = 0\ or\ x = 13$

This matches with the option C.

5 0

2 years ago

Explain why an account balance less than -40 dollars represents a dept greater than 40 dollars

nevsk [136]

You need to pay $40 to make your balance 0 and then another $40 to make it $40.
In all you will have to pay $80

8 0

3 years ago