What is the GCF of the numerator and denominator in the following fraction? -
1 answer:
You might be interested in
Answer:
<u>Perimeter</u>:
= 58 m (approximate)
= 58.2066 or 58.21 m (exact)
<u>Area:</u>
= 208 m² (approximate)
= 210.0006 or 210 m² (exact)
Step-by-step explanation:
Given the following dimensions of a rectangle:
length (L) = meters
width (W) = meters
The formula for solving the perimeter of a rectangle is:
P = 2(L + W) or 2L + 2W
The formula for solving the area of a rectangle is:
A = L × W
<h2>Approximate Forms:</h2>In order to determine the approximate perimeter, we must determine the perfect square that is close to the given dimensions.
13² = 169
14² = 196
15² = 225
16² = 256
Among the perfect squares provided, 16² = 256 is close to 252 (inside the given radical for the length), and 13² = 169 (inside the given radical for the width). We can use these values to approximate the perimeter and the area of the rectangle.
P = 2(L + W)
P = 2(13 + 16)
P = 58 m (approximate)
A = L × W
A = 13 × 16
A = 208 m² (approximate)
<h2>Exact Forms:</h2>
L = meters = 15.8745 meters
W = meters = 13.2288 meters
P = 2(L + W)
P = 2(15.8745 + 13.2288)
P = 2(29.1033)
P = 58.2066 or 58.21 m
A = L × W
A = 15.8745 × 13.2288
A = 210.0006 or 210 m²
Answer:
A
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y = ( multiply both sides by x³ )
x³y = 19 ( divide both sides by y )
x³ = ( take the cube root of both sides )
x =
Change y back into terms of x, then
(x) =
=
→ A