1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
erma4kov [3.2K]
3 years ago
8

The sum of a number and two times a smaller number is 62. three times the bigger number exceeds the smaller number by 116. the b

igger number is . the smaller number is
Mathematics
1 answer:
Semmy [17]3 years ago
3 0
X+2y=62
3x-2y=116

solving the simultaneous equations by multiplying first equation by 3;
3x+6y=186
3x-y=116

Subtracting equation II from equation I;
7y=70
y=10
 Replacing y in equation I;

x+20=62
x=42

Bigger number is 42 and smaller number is 20.


You might be interested in
List four real -word objects that rotate
ArbitrLikvidat [17]

Answer:

planet

atom particles

ball

and child

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
The diagram represents 6x^2-7x+2with the factor of 2x-1. What is the factor of 6 x^2-7x+2
Maksim231197 [3]

Answer:

(6x²-7x+2)/2x-1

(2x-1)(3x-2)/2x-1

=

<h2>3x-2</h2>
5 0
3 years ago
Read 2 more answers
The sum of a number times 8 and 21 is less than -16.
vodka [1.7K]

Hello.

First of all, let the number be t.

8 times t can be written like this:

\mathrm{8t}

Notice that the number is before the variable and the times sign (×) is not there.

We can write it as 8×t, but we usually write it as 8t.

The sum of means we add:

8t+21

Now, "less than" is "<" :

\mathrm{8t+21 < -16}

Therefore, the answer is

\mathrm{8t+21 < -16}

I hope it helps.

Have a nice day.

\boxed{imperturbability}

7 0
2 years ago
Write the ratio as a fraction in lowest terms. Be sure to make necessary conversions:
agasfer [191]

Answer:12533

Step-by-step explanation:

4 0
2 years ago
A company is to hire two employees. They have prepared a final list of eight candidates, all of whom are equally qualified. Of t
Softa [21]

Answer:

i) Probability that both candidates employed are women = 5/14

ii) Probability that the second candidate is a woman = 5/8

iii) Probability that the first candidate is a woman given that second one is a woman = 4/5

Step-by-step explanation:

Let the probability that a man is employed be P(M) = 3/8

Probability that a woman is employed P(W) = 5/8

a) Probability that both candidates employed are women = (5/8) × (4/7) = 5/14

b) Probability that the second candidate is a woman = (probability that first candidate is a man and second candidate is a woman) + (probability that first candidate is a woman & second candidate is a woman)

= (3/8)(5/7) + (5/8)(4/7) = (15/56) + (20/56) = 35/56 = 5/8

c) Probability that the first candidate is a woman given that second one is a woman

Given that the second candidate was a women, means that the first candidate-women was selected among other four women.

Probability = (4/8)/(5/8) = 4/5

7 0
2 years ago
Other questions:
  • How to find matrics M
    6·1 answer
  • Two row boats start at the same location, and start traveling apart along straight lines which meet at an angle of π3. Boat A is
    6·1 answer
  • Solve for b.<br><br> −13b=9 plees help
    12·2 answers
  • How do you check your answer for volume of a cylinder? Desperate need of answering
    9·1 answer
  • an electrician was hired to wire a new house. In 11 1/4 days he estimates he has completed 70% of the job. At his current pace o
    12·1 answer
  • 73590 rounded to the nearest thousand
    14·1 answer
  • Larry gets $7 for each of the 3 flower beds he weeds and Y dollars to edge a yard. Zach will get $25 to clean a garage and Y dol
    15·1 answer
  • What is the measurement of Angle O in parallelogram LMNO. When angle L is (x+40) and angle O is (3x)
    5·2 answers
  • What is the slope of the line that intersects these two points?
    9·1 answer
  • What is the value of f(3) in the function below?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!