The sum of a number and two times a smaller number is 62. three times the bigger number exceeds the smaller number by 116. the b
igger number is . the smaller number is
1 answer:
X+2y=62
3x-2y=116
solving the simultaneous equations by multiplying first equation by 3;
3x+6y=186
3x-y=116
Subtracting equation II from equation I;
7y=70
y=10
Replacing y in equation I;
x+20=62
x=42
Bigger number is 42 and smaller number is 20.
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