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sashaice [31]
3 years ago
13

12 rounded to the nearest tenth in between 167

Mathematics
1 answer:
Alex777 [14]3 years ago
4 0

0 dude it's 0. I know now you know.

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Megan wants to build a fence around her pool. The pool is 28 feet long by 23 feet wide. The fence is to be 15 feet from the edge
marshall27 [118]
To determine the amount of fencing needed to enclose the pool area, you will need to add 15 feet to both sides of both dimensions to find the new dimensions that will need enclosed.

28 feet + 15 feet + 15 feet =  58 feet

23 feet + 15 feet + 15 feet = 53 feet

The fence will need to be 2 x 58 + 2 x 53 or 222 feet long for the 53 feet by 58 feet area.

5 0
3 years ago
Solve equation x/6+4=15
RoseWind [281]

x/6+4= 15


Subtract 4 from both sides; 4s cancel each other out

x/6+4-4= 15-4


x/6= 11


multiply both sides by 6 to eliminate fraction (multiply by reciprocal of 1/6)

(x/6)(6)= (11)(6)


x= 66



ANSWER: x= 66


Hope this helps! :)

8 0
4 years ago
Read 2 more answers
FREE BRAINLIEST TO EVERYONE WHO ANSWERS RIGHT!!
My name is Ann [436]

Answer:

x4

Step-by-step explanation:

8 0
3 years ago
The wind speed s (in miles per hour) is related to the distance (in miles) the tornado travels by the equation s = 93log d + 65.
Vesnalui [34]

Answer:

The distance the tornado traveled was approximately 205 miles.

Step-by-step explanation:

The equation representing the relationship between the wind speed (in miles per hour) and the distance the tornado travels (in miles) is:

s=93\log d+65

Compute the value of <em>d</em> for <em>s</em> = 280 as follows:

        s=93\log d+65

     280=93\log d+65

93\log d=280-65\\93\log d=215

   \log d=2.312\\

        d=10^{2.312}\\d=205.035\\d\approx 205

Thus, the distance the tornado traveled was approximately 205 miles.

7 0
3 years ago
Hey can you please help me!
melisa1 [442]

Answer:


Step-by-step explanation:

1) Tangent makes 90 degrees with the radius. Hence

a) Angle ABD = 90-angle BDC = 90-61.3 = 28.7

b) Triangle BCD is isosceles since tangents have equal length.

Hence angle BCD = 180-(61.3+61.3) = 57.4

c) Angle BDC = 57.4 (since triangle BCD is isosceles)

d) Angle BAC and Angle BCD are supplementary. Hence angle BAC = 122,6

-------------------------------------------

2) Arc length of minor arc BC = \frac{79.3}{360} (24) = 5.287

b) ARc length of minor arc = circumference -minor arc

= 18.713

---------------------------------------------

3) circumference = pi d = 3.14(9) = 28.26


6 0
4 years ago
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