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EastWind [94]
3 years ago
15

3√10 x 2√15 = i need the steps too please it’s for algebra 2.

Mathematics
1 answer:
irina [24]3 years ago
5 0

Answer:

30√6

Step-by-step explanation:

3√10 ×2√15= 6√150=30✓6

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A scatter plot showed a positive correlation for 11 bowlers. As the number of strikes, s, a bowler made in a game increased, the
almond37 [142]

Answer:

s = 4

Step-by-step explanation:

The equation for the line of best fit for the data is p=25s+40.

Where p is no. of points and s is no. fo strikes

We need to find the number of strikes made by a bowler with 140 points.

Put p = 140

p=25s+40

140 = 25s+40

Subtract 40 to both sides,

140-40 = 25s+40-40

100 = 25s

⇒ s = 4

So, there are 4 strikes made by a bowler with 140 points.

5 0
3 years ago
Can someone check my answer please HELP!
Bezzdna [24]
Let price of one scarf be $x 
Price of the other is 3 more than $x
 Therefore price of the other scarf =$x +3
 The total price she paid = $25.00
 That is, x+x+3=25
  2x+3=25
  2x=25-3
  2x=22
  x=22/2
  x=11
 The price of one scarf is $11 and the price of the other is 11+3=$14
 The price of the expensive scarf =$14.
6 0
3 years ago
A easy question help.
Citrus2011 [14]

Answer:

170ft

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The weights of packets of cookies produced by a certain manufacturer have a Normal distribution with a mean of 202 grams and a s
Evgen [1.6K]

Answer:

209.005 gms

Step-by-step explanation:

Given that the weights of packets of cookies produced by a certain manufacturer have a Normal distribution with a mean of 202 grams and a standard deviation of 3 grams.

Let X be the weight of packets of cookies produced by manufacturer

X is N(202, 3) gms.

To find the  weight that should be stamped on the packet so that only 1% of the packets are underweight

i.e. P(X<c) <0.01

From std normal table we find that z value = 2.335

Corresponding x value = 202+3(2.335)

=209.005 gms.

5 0
3 years ago
Alex wrote 103.903 in expanded form as 100+3 x 1+9 x 1/100 +3 x 1/1000. Explain his mistake then tell how to correct it.
Damm [24]
Your mistake was in this part  9 x 1/100 . After the decimal point the place value starts with tenths so you should write 9 x 1/10 .

Place values

Before the decimal point

3 ones = 3 x 1

0 tens = 0 x 10

1 hundreds = 1 x 100

After the decimal point

9 tenths = 9 x 1/10

0 hundredths = 0 x 1/100

3 thousandths= 3 x 1/1000

1 x 100 + 0 x 10 + 3 x 1 + 9 x 1/10 + 0 x 1/100 + 3 x 1/1000

  100     +    0     +   3    +    0.9      +     0        +    0.003

           100         + 3      +          0.9                +     0.003 =  103.903

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8 0
3 years ago
Read 2 more answers
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