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Nikolay [14]
3 years ago
14

Use the discriminant of the following quadratic equation to state the number and type of solutions. 3x^(2)+4x-5=3x+2

Mathematics
1 answer:
krek1111 [17]3 years ago
4 0
3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions
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The completely factored form of the provided polynomial is  (p -2) (p+ 2) (p² +4). The option 4 is the correct option.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is a real number).

The polynomial equation given in the problem is,

p^4 - 16

Let the factor form of the polynomial is f(p). Thus,

f(p)=p^4 - 16\\f(p)=p^4 - 2^4\\f(p)=(p^2)^2- (2^2)^2

Using the formula of difference of squares, we get,

f(p)=(p^2-4)(p^2+4)\\f(p)=(p^2-2^2)(p^2+4)\\f(p)=(p-2)(p+2)(p^2+4)

Thus, the completely factored form of the provided polynomial is  (p -2) (p+ 2) (p² +4). The option 4 is the correct option.

Learn more about polynomial here;

brainly.com/question/24380382

3 0
2 years ago
Is my solution correct?
nlexa [21]

Hello there!

Yes, your solution is correct! A way to check it is replacing the value you found for x into x in the equation.

3(2-x) = 7 - 4x ⇒ 3(2-1) = 7 - 4(1)

And now solve  3(2-1) = 7 - 4(1).

3(1) = 7 - 4(1)

3 = 7 - 4

3 = 3

Since it is a true statement that 3 is equal to 3, it means your solution of x = 1 is correct. Good job! :)

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