We can solve this by looking at pairs that equal 60.
6 and 10 get to 60 when multiplied. Let's see if it fits in as a perimeter.
12+20=32
So the width and length of the room is 6 meters and 10 meters.
58 divide 10= 5 remainder 8
(Remember to show your work!)
Answer: the answer is 141 or 126
Step-by-step explanation:
First answer (x=-2)
...
(2)[(-2)^2]+6-20
2(4)+6-20
8+6-20
14-20
<em>-6 (answer)
</em><em>
</em><em />Second answer (x=5)
...
(2)[(-5)^2]+6-20
2(25)+6-20
50+6-20
56-20
<em>36 (answer)
</em>Hope this helps!
