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-Dominant- [34]
3 years ago
8

How to substitute x=-2 and x=5 into 2x^2+6-20=0 to check my work

Mathematics
1 answer:
Komok [63]3 years ago
4 0
First answer (x=-2)
...
(2)[(-2)^2]+6-20
2(4)+6-20
8+6-20
14-20
<em>-6 (answer)
</em><em>
</em><em />Second answer (x=5)
...
(2)[(-5)^2]+6-20
2(25)+6-20
50+6-20
56-20
<em>36 (answer)
</em>Hope this helps!
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<em>a) 1 </em>

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