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3 years ago

What's the taxes on $1,500

Mathematics

1 answer:

Bumek [7]3 years ago

5 0

It depends on the percentage rate of said tax... is the tax rate 5%? 20%?

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C = 188.4in <br> What’s the answer

Advocard [28]

Answer:

Well from where the equation is now, I don't see any further things I can do. What is the context of the problem?

Step-by-step explanation:

7 0

3 years ago

Find the number of hours each person work

Lina20 [59]

J stands for Jon, A stands for Angelica, and C stands for Chaya.

J = C - 3
A = C + 4
C = A - 4

= 196 h

62 + 65 + 69 = 196

Jon worked 62 hours, Chaya worked 65 hours, and Angelica worked 69 hours.

And that's your answer! ^ I hope this helped you! c:

6 0

3 years ago

solve systems of equation. equation number 1: 9 x squared + 4 y squared equals 144. equation 2: x squared plus y squared equals

grigory [225]

$9x^{2} + 4y^{2} =144$
$x^{2} + y^{2}=24$

$9x^{2} + 4y^{2} =144$
$4x^{2} + 4y^{2}=96$
by the difference
5 $x^{2}$ =48
so x= $\sqrt{\frac{48}{5}}$ or x=- $\sqrt{\frac{48}{5}}$
and $y^{2}$ =24- $\frac{48}{5}$
then y= $\sqrt{\frac{72}{5}}$ or - $\sqrt{\frac{48}{5}}$

5 0

3 years ago

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

6 0

3 years ago

Please help me please!<br> Also, please show your work image shown below in attachment

WINSTONCH [101]

Answer:

see below

Step-by-step explanation:

some of your answers that you currently have are wrong, I'll note those mistakes below

- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio

5x+15 = 5(x+3), not (x+3)(x+5)

ie $\frac{10x^2+20x}{x+2}$

we see that 10x can divide the numerator in a whole number ratio

$10x^2+20x$ = 10x(x+2), not (x+2)(x+10)

second mistake: the first binomial expansion is incorrect.

you have the expansion formula right, but you added terms wrong, go look at it again

3. x^2+3x+2/ x^2+5x+6

(x+1)(x+2)/(x+3)(x+2)

(x+1)/(x+3)

4. (x^2+6x+8)/(x^2-16)

(x+4)(x+2)/(x+4)(x-4)

(x+2)/(x-4)

5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator

6. (x^4y^6)^2

(x^4y^6)(x^4y^6) = $x^8y^{12}$

remember that (x^a)(x^b) = x^(a+b)

or remember that (x^a)^b = x^ab

6 0

3 years ago