We have the following data:
Margin of Error = E = 2.7 % = 0.027
Sample size = n = 900
Proportion of adults in favor = p = 60% = 0.6
We need to find the confidence level. For this first we need to find the z value.
The margin of error for a population proportion is given as:

Using the values, we get:
As, seen from the z table, z=1.65 corresponds to the confidence level 90%. So, the answer to this question is option B
<span>valid. She used a representative sample
</span>because she correctly found the average and 18,000 is a reasonable number to get for a the problem
Put it in the form
ax^2 + bx + c = 0
use the quadratic formula
x = [ -b + sqrt( b^2 - 4 ac ) ] / 2a
x = [ -b - sqrt( b^2 - 4 ac ) ] / 2a
7v^2 - 7v - 22 = 0
a = 7
b = -7
c = -22
v = [ 7 + sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = 2.34
v = [ 7 - sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = -1.34
To answer the question above, evaluate the number of cookies each of them placed on a tray. The calculations are shown below,
Ronny C1 = 0.15 x 20 = 3
Celina C2 = 3
Jack C3 = 0.30 x 20 = 6
Michelle C4 = 20 - (3 + 3 + 6) = 8
From the calculation above, <em>Michelle</em> placed the most number of brownies on the tray.
Answer:
It would be -7
Step-by-step explanation:
The 12 is negative, so instead of adding, you would subtract 5.