Answer:
y=3/2x-5
when finding the equation of a line, we use this formula
y=mx+b
where Y= a point on the y-axis
M= ∆y/∆x
x= a point on the x-axis
and b = intercept
Step-by-step explanation:
so to in this case, we are given y= 4, x=6 and y-int = -5
substitute the value in the given equation,
therefore, 4=6m-5
4+5=6m
9/6=M
3/2=m
Answer y=3/2x-5 that is the equation of the line
C. multiply the second equation by two. Then add the equations
Answer:
khjkug
Step-by-step explanation:
-2y=11-x
-7x+11-x=-13
-8x=-24
x=3
-2y=11-3
-2y=8
y=-4
Y=ax+b, y=cx+d (a≠0, c≠0)
If the two line cross perpendicularly ⇔ ac= -1
So a tangent of the perpendicular line is "-(1/5)".
Then, the equation of the perpendicular line is y=-(1/5)x+a (a is <span> y-intercept</span>).
On the other hand, this equation pass r(1, 3), so
3 = -(1/5) times 1 + a
∴ a=16 / 5
Therefore, y=-(1/5)x+16 /5 is answer.
By the way, I'm Japanese so if you find some mistakes in my English, please let me know.