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vredina [299]
3 years ago
13

sharon is making greeting cards, each card takes her twenty minutes to make. how many can she complete in two and a half hours?

Mathematics
1 answer:
olga2289 [7]3 years ago
4 0
7 or 8 since 2 and a half hours isnt an even amount of time so thered be an extra 10 minutes
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List the ordered pairs in the equivalence relations produced by these partitions of {a, b, c, d, e, f, g}: a) {a,b},{c,d},{e,f,g
finlep [7]

Answer:

a)  {a,b} , {c,d} , {e,f,g},{a , b } = {(a,a) (b,b) (a,b) (b,a)},{c , d } = {(c,c) (d,d) (c,d) (d , c) } ,{e,f,g} = {(e,e) (e,f)  (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f)(g,g)}  

b) { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)

c)  {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

Step-by-step explanation:

a) {a,b} , {c,d} , {e,f,g}

  {a , b } = {(a,a) (b,b) (a,b) (b,a)}

  {c , d } = {(c,c) (d,d) (c,d) (d , c) }

  {e,f,g} = {(e,e) (e,f)  (f,e)  (e,g) (f,f) (f,g) ( g,e) (g,f) (g,g)}  

b) {a} ,{b},{c,d} ,{e,f},{g}

     { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)}

c)  {a,b,c,d},{e,f,g}

   {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

4 0
3 years ago
Pls help me calculate the total area of compound shapes?!?!?
Elza [17]

Answer:

Left: 42ft^2

Right: 21ft^2

Step-by-step explanation:

Its the same question as last time.

Left: (3*10) + (2*6) = 42

Right: (3*5) + (2*3) = 21

4 0
1 year ago
Can someone help me?
sattari [20]

Answer:

176 cubic feet I think

Step-by-step explanation:

352 / 2 = 176

7 0
3 years ago
Read 2 more answers
10110, written in base 10 is
Fantom [35]
A fake link ........................
3 0
2 years ago
I need help asap with this
tatyana61 [14]

Answer:

51°

Step-by-step explanation:

Given

<QPR = 39°

<PQR = 90° ( inscribed angle in semi circle)

Now

<QPR + <PQR + <PRQ = 180° { being sum of angles of triangle)

39° + 90° + <PRQ = 180°

<PRQ = 180° - 39° - 90°

<PRQ = 51°

Hope it will help :)

5 0
2 years ago
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