We can start by solving for 10-5a+(18-b). By plugging in a and b, we get
10 - 10 + (18 - 11)= 7
28 ÷ (a × 2) = 28/4 = 7
20 + b − (4 × a) = 31 - 8 = 23
49 − 43 + (a ÷ a) = 49 - 43 + 1 = 7
30 − 25 + (b − 9) = 5 + 2 = 7
50 ÷ a − (b + 20) = 25 - 31 = -6
So, 28 ÷ (a × 2), 49 − 43 + (a ÷ a), and 30 − 25 + (b − 9) will all have the same answer as 10−5a+(18−b)
\left[x \right] = \left[ -3+\frac{3\,y}{2}\right][x]=[−3+23y] this is answer
Answer:
(-1,0)
Step-by-step explanation:
Convert the equation to vertex form which becomes y=(x+1)^2+0
Then we can see the vertex in the form (h,k) in y=a(x-h)^2+k
Okay. First off, let’s solve for the first two sides, since they are the same length. Set it up like this: 8x - 4 = 5x + 11. Subtract 5x from both sides to get 3x - 4 = 11. Next, add 4 to both sides to get 3x = 15. Now, divide each side by 3 to isolate the x and you get 5. Let’s plug in the values. 8 * 5 = 40 - 4 = 36. 5 * 5 = 25 + 11 = 36. There. x = 5. Now, let’s plug the 5 in to the other formula. 5 * 4 = 20. 20 - 2 = 18. There. BC is 18 units long.
Answer:
1.30
Step-by-step explanation:
3+5x=7
Subtract 3 on both sides, 3 will cancel out on the left side and will subtract by 7 making it 4
5x=4
Then divide by 5 on both sides to isolate the x.
5/4=1.25
1.25 rounds to 1.3
Hope this helps C:
