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3 years ago

Please helppp!! For the equation y = 3x – 6 Complete the table for the x values given.

Mathematics

1 answer:

enot [183]3 years ago

6 0

Answer:

Step-by-step explanation:

y = 3x -6

x = -2, y = -12

x = -1, y = -9

x = 0, y = -6

x = 1, y = -3

x = 2, y = 0

x= 3, y = 3

x -2 -1 0 1 2 3

y -12 -9 -6 -3 0 3

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Your friend is wrapping 1 meter of twine around a spool with a 2-centimeter diameter. The spool is thin and accommodates only on

Kazeer [188]

Answer:

a) 6 complete times

b) 19.3%

Step-by-step explanation:

In every turn, the diameter of the twine increases 1 cm.

After the first turn, there is a total wrapped of 3.14*2=6.3 cm.

After the second turn, we have wrapped 6.3+3.14*(2+1)=15.7 cm.

If we continue with these algorithm, we have that after the 6th turn we have 84.8 cm wrapped. <em>This is the last complete turn.</em>

T = 0 D = 2 cm. Wrapped = 6.3 cm. Total wrapped = 6.3 cm.

T = 1 D = 3 cm. Wrapped = 9.4 cm. Total wrapped = 15.7 cm.

T = 2 D = 4 cm. Wrapped = 12.6 cm. Total wrapped = 28.3 cm.

T = 3 D = 5 cm. Wrapped = 15.7 cm. Total wrapped = 44 cm.

T = 4 D = 6 cm. Wrapped = 18.8 cm. Total wrapped = 62.8 cm.

T = 5 D = 7 cm. Wrapped = 22.0 cm. Total wrapped = 84.8 cm.

T = 6 D = 8 cm. Wrapped = 25.1 cm. Total wrapped = 110 cm.

There are left (100-84.8) = 15.2 cm to wrap around the twine, which has a 25.1 cm diameter by now.

The perimeter of the twine is 3.14*25.1=78.8 cm.

The percentage of a complete circle that the last wrapping of the twine will make is:

P = 15.2/78.8 = 0.193 = 19.3%

4 0

3 years ago

Help me please m, it due soon

allsm [11]

Surface area= 2(6x15)+2(7x15)+2(6x7)
=180+210+84
=474m

Volume=15x6x7
=630m^2

5 0

3 years ago

Sound travels through sea water at a speed of about 1500 meters per second. At this rate, how far will sound travel in 2 minutes

Mariulka [41]

Answer:

180,000 m

Step-by-step explanation:

There are 60 seconds in a minute, so:

2 min × 60 s/min = 120 s

Distance = rate × time

d = 1500 m/s × 120 s

d = 180,000 m

8 0

3 years ago

For an angle θ, tan(θ) is a negative number. Which quadrants might θ be in?

Klio2033 [76]

So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.

4 0

2 years ago

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In science class, Priscilla heats water and measures the temperature of the water every 2 minutes\or data are shown in the table

Dima020 [189]

Answer:

37.5 °C

Step-by-step explanation:

The temperature appears to be increasing linearly at the rate of 5 °C in 2 minutes, or 2.5 °C per minute.

1 minute after 4 minutes, when the temperature is 35 °C, we expect it to be 2.5 °C higher, or 37.5 °C.

8 0

3 years ago