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alexgriva [62]
2 years ago
13

The quantity of heat required to change the temperature of 1 g of a substance by 1 c is defined as

Chemistry
1 answer:
slega [8]2 years ago
6 0
I think it's calorie
Hope this helps
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Which atomic property is different in each isotope of an element?
slava [35]
Mass number...use da textbook bra
6 0
3 years ago
Write ionic formulas for the following compounds:
lakkis [162]

You may find the chemical formulas for the ionic compounds below.

Explanation:

a. Calcium Bromide - CaBr₂

b. Potassium Phosphide  - K₃P

c. Iron (III) Oxide  - Fe₂O₃

d. Iron (II) Oxide  - FeO

e. Magnesium Hydroxide  - Mg(OH)₂

f. Nickel (III) Sulfate​ - Ni₂(SO₄)₃

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 chemical formulas of ionic compounds

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6 0
3 years ago
I NEED HELP ASAP DON'T JUST ANSWER FOR POINTS OR YOU WILL GET REPORTED!
White raven [17]

Answer:

The number of neutrons is entirely dependent on the Mass number of the particular atom. The standard mass for potassium is 39.

Potassium is element number 19, so it has 19 protons and 19 electrons in the neutral atom. It has therefore 39-19 = 20 Neutrons.

Explanation:

7 0
2 years ago
Read 2 more answers
A solution has a<br> pH of 2.5.<br> Answer the following questions.<br> pOH =<br> [H]=<br> [OH]=
Sloan [31]

Answer:

pOH = 11.5

[H⁺] = 0.003 M

[OH⁻] = 3 × 10⁻¹² M

Explanation:

The computation is shown below:

Given that

pH = 2.5

Based on the above information

We know that

pH + pOH = 14  ⇒  pOH = 14 - pH

pOH = 14 - 2.5

pOH = 11.5

[H⁺] = 10^(-pH) = 10^(-2.5)

[H⁺] = 0.003 M

[OH⁻] = 10^(-pOH)

= 10^(-11.5)

= 3 × 10⁻¹² M

[OH⁻] = 3 × 10⁻¹² M

Hence, the above represents the answer

4 0
2 years ago
4NH3(g) + 5O2(g) 4NO(g) + 6H2O(g)
Crazy boy [7]

1. The volume of ammonia consumed in the reaction is 23.2 L

2. The volume of oxygen consumed in the reaction is 29 L

<h3>Balanced equation</h3>

4NH₃(g) + 5O₂(g) --> 4NO(g) + 6H₂O(g)

From the balanced equation above,

6 L of H₂O were produced from 4 L of NH₃ and 5 L of O₂

<h3>1. How to determine the volume of ammonia, NH₃ consumed</h3>

From the balanced equation above,

6 L of H₂O were produced from 4 L of NH₃

Therefore,

34.8 L of H₂O will be produced from = (34.8 × 4) / 6 = 23.2 L of NH₃

Thus, 23.2 L of NH₃ were consumed

<h3>2. How to determine the volume of oxygen, O₂ consumed</h3>

From the balanced equation above,

6 L of H₂O were produced from 5 L of O₂

Therefore,

34.8 L of H₂O will be produced from = (34.8 × 5) / 6 = 29 L of O₂

Thus, 29 L of O₂ were consumed

Learn more about stoichiometry:

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#SPJ1

7 0
1 year ago
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