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NISA [10]
2 years ago
15

A Jaguar runs 4209 meters at the of 1400 meters per minute

Chemistry
1 answer:
Scorpion4ik [409]2 years ago
4 0
Could you please describe the question?

lmk once you are done!!

support me by marking as brainliest!!
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Some animals only have ___ cell.
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Animal cells have a centrosome and lysosomes, whereas plant cells do not.
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How many moles of sodium (Na) are there in a<br> sample of 5.87 x 1024 atoms of sodium?
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9.74x 2351 that's the answer
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3 years ago
PLSSS HELP ASAPP ITS 200 points and I give brainlist
Ad libitum [116K]

1. should be A

Explanation:

because that's what I got

6 0
3 years ago
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What is the mass percent of nitrogen in ammonium carbonate, (NH4)2CO3?
Margaret [11]

In order for you to calculate for the mass of ammonium carbonate, you need to know the molar mass of it and the nitrogen atoms in the compound. Ammonium carbonate has a molar mass of 96.08 grams per mole. There are two nitrogen atoms in ammonium carbonate which is equal to 28.02 grams per mole. Divide the molar mass of nitrogen to the ammonium carbonate, 28.02/96.08 x 100, we get 29.16wt% nitrogen.

6 0
3 years ago
1. Complete the following
Marat540 [252]

Answer:

\large \boxed{\text{0.603 mol}}

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of O₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:        180.16

           C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g:        18.1

(a) Moles of C₆H₁₂O₆

\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{18.1 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1005 mol C$_{6}$H$_{12}$O}_{6}

b) Moles of O₂

\text{Moles of O}_{2} =\text{0.1005 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol O}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.603 mol O}_{2}\\\\\text{The reaction requires $\large \boxed{\textbf{0.603 mol}}$ of oxygen}  

3 0
2 years ago
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