All categories

3 years ago

Need help please ? I don’t understand nothing that much

Chemistry

2 answers:

Kitty [74]3 years ago

6 0

Answer:

The two middle answers. 100 degrees C and 212 degrees F.

Explanation:

The boiling point for water does not change. Also it is stated at the bottom of the paragraph.

wolverine [178]3 years ago

4 0

Answer:

Both C and D

Explanation:

The description tells you the answer.

You might be interested in

O2is which of the following? A. Molecule B. compound C. both compound and molecule D. one atom

valkas [14]

Answer:

it is a molecule

Explanation:

it is not a compound because compounds are made up from two or more different elements

4 0

3 years ago

Read 2 more answers

What is the boiling point of a solution made using 759 g of sucrose, c12h22o11, in 0.300 kg of water, h2o?

Ray Of Light [21]

According to the boiling point elevation formula:

ΔTb = i * Kb * m

- when i is the van't Hoff factor for sucrose = 1

as the sucrose is an organic molecule so, there is no dissociation in water so i = 1
- Kb is the ebullioscopic constant of the solvent (water) = 0.512°C Kg mol-1

- and when m is the molality = moles sucrose / Kg water

so, we need first to get moles sucrose = mass/molar mass

= 759 g / 342.3 g/mol

= 2.22 moles

∴ m = 2.22 moles / 0.3 Kg

= 7.4 mol/kg

by substitution on ΔTb:

∴ΔTb = 1 * 0.512 * 7.4

= 3.8

∴Tb = 100 °C + 3.8 = 103.8 °C

3 0

3 years ago

I will give 100 points to anyone who friends me

Annette [7]

Answer:

i doubt that but i'll friend you anyways.. haha

Explanation:

Thanks for the points

7 0

2 years ago

Read 2 more answers

The second-order rate constant of the reaction CH3COOC2H5(aq) CH3CO2-(aq) CH3CH2OH(aq) is 0.11dm3mol-1s-1. What is the concentra

grigory [225]

Answer:

This is the complete part of the question ; the initial concentration are [NaOH]= 0.06 mol/dm^3 and [CH3COOC2H5]=0.110 mol/dm^3 ?

a) concentration of ester (CH3COOC2H5) after 20s = 0.098mol/dm3

b) concentration of ester (CH3COOC2H5) after 15mins = 0.1010mol/dm3

Explanation:

The detailed derivation of second order rate law from first principle and the appropriate substitution is a shown in the attachment.

5 0

3 years ago

Acetylene (C2H2) has a tendency to lose two protons (H1) and form the carbide ion (C2 22), which is present in a number of ionic

Ilia_Sergeevich [38]

Answer:

The C22- ion is stable

Explanation:

The C22- ion is a stable ion having a bond order of three. It has a favourable stabilization energy of 6∆ compared to 4∆ in C2. In the carbide ion carbon firms three bonds rather than two in dicarbon, hence the formation of the carbide ion is preferred. The molecular orbital configuration of the carbide ion is shown in the image attached.

4 0

4 years ago