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2 years ago

9

The flag of a country contains an isosceles triangle. (Recall that an isosceles triangle contains two angles with the same mea

sure.) If the measure of the third angle of the triangle is 30° more than three times nbspthree times the measure of either of the other two angles, find the measure of each angle of the triangle. (Recall that the sum of the measures of the angles of a triangle is 180°.)

1 answer:

r-ruslan [8.4K]2 years ago

4 0

No our flag is a triangle just kidding it’s a circle

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Identify whether the function graphed has an odd or even degree and a positive or negative leading coefficient.

Shtirlitz [24]

Answer:

odd degree and positive leading coefficient

Step-by-step explanation:

From the graph , we can see that when x goes to infinity , y goes to infinity

As x--> ∞, y--> ∞ (As x increases the value of y increases on the positive side)

we can see that when x goes to -infinity , y goes to -infinity

As x--> -∞, y--> -∞ (As x decreases the value of y decreases on the negative side)

When x--> ∞, y--> ∞ and x--> -∞, y--> -∞

The leading coefficient is positive and largest exponent is odd

So the graph has odd degree and positive leading coefficient

8 0

2 years ago

I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

2 years ago

Expand. Your answer should be a polynomial in standard form. (x2+4)(x2−6)=(x^2+4)(x^2-6)=(x2+4)(x2−6)=

Dafna11 [192]

Answer:

x^4 -2x^2 -24

Step-by-step explanation:

(x^2+4)(x^2−6)

FOIL

First: x^2*x^2 = x^4

Outer: x^2 *-6 = -6x^2

Inner: x^2 *4 = 4x^2

Last: 4*-6 = -24

Add them together

x^4 -6x^2 +4x^2 -24

Combine like terms

x^4 -2x^2 -24

This is in standard form since the powers decrease

8 0

2 years ago

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Jada bought 3 shirts that cost $19.99 each before discount. What was her total after the discount? The percentage discount at a

Alex777 [14]

Total after the discount would be $77.96

7 0

3 years ago

What is the selling price of a 62.25 karaoke machine with a 60.55 mark up

Mice21 [21]

Answer:

$122.80

Step-by-step explanation:

$62.25 + $60.55 = $122.80

Hope this helps. Please mark brainliest.

3 0

2 years ago