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olasank [31]
3 years ago
13

1. The parameter "a": Compare the graphs of several different exponential growth functions in

Mathematics
1 answer:
Helga [31]3 years ago
6 0

Answer:

See explanation

Step-by-step explanation:

Required

The significance of "a" in exponential function

An exponential function is represented as:

y = ab^x

In the above equation, parameter "a" is the initial value of the function

In other words, the value of the function when x = 0

Take for instance;

y = 2*4^x

a = 2 because when x = 0

y = 2 * 4^0

y = 2 * 1

y = 2

Another significance of parameter a is that; it is the y-intercept of the geometric function.

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Find the value of the formula using the numbers given <br> B=8x+9b when b=1.25 and x=2.25
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Answer:

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find continued product of (x+y) (x-y) (<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}"
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Answer:

\large\boxed{(x+y)(x-y)(x^2+y^2)(x^4+y^4)=x^8-y^8}

Step-by-step explanation:

(x+y)(x-y)(x^2+y^2)(x^4+y^4)\\\\\text{use}\ (a-b)(a+b)=a^2-b^2\qquad(*)\\\\=\underbrace{(x+y)(x-y)}_{(*)}(x^2+y^2)(x^4+y^4)\\\\=\underbrace{(x^2-y^2)(x^2+y^2)}_{(*)}(x^4+y^4)\\\\=\left((x^2)^2-(y^2)^2\right)(x^4+y^4)\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\underbrace{(x^4-y^4)(x^4+y^4)}_{(*)}\\\\=\left(x^4\right)^2-\left(y^4\right)^2=x^8-y^8

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