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Gemiola [76]
3 years ago
13

Tom is tiling a wall.

Mathematics
1 answer:
krok68 [10]3 years ago
3 0

Answer:

The correct answer is - £ 40.5 for 3 large packs.

Step-by-step explanation:

Given:

Large pack = 40 tiles £18

Small pack = 28 tiles £14

Special offer = 25% reduction when you buy 3 or more large packs.

Solution:

Following combinations are possible for tom to get the tiles he needs:

1. 3 large packs

40*3 = 120 tiles with 25% discount

cost = 18*3 - 0.25*18*3 = 40.5

2. 4 small packs

28*4 = 112 tiles

cost = 14*4 = 56

3. 2 large packs and 1 small pack

40*2 + 28 = 108 tiles

cost = 18*2 + 14 = 50

4. 1 large pack and 3 small packs

40 + 28*3 = 124 tiles

cost = 18 + 14*3 = 60

Thus, the correct answer is - 1st case with three large packs.

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Please include work!
geniusboy [140]

Answer:

x = ± 4

y = - 2

Step-by-step explanation:

y = 0.5x² - 10 ------------------------(I)

y = -x² + 14   ------------------------(II)

Substitute the y value in equation (II)

    0.5x² - 10  = -x² + 14           {Add x² to both sides}            

0.5x² + x² -10 = 14                  {combine like terms}

       1.5x² - 10 = 14                   {Add 10 to both sides}

               1.5x² = 14 + 10

                1.5x² = 24         {Divide both sides by 1.5}

               1.5x²/1.5 = 24/1.5

                       x² = 16

                      x = ±4

Substitute x = 4 in (I)

y = 0.5 * 4² - 10

 = 0.5*16 - 10

 = 8- 10

y = -2

Substitute x = -4 in (I)

y = 0.5 * (-4)² - 10

 = 0.5*16 - 10

 = 8- 10

y = -2

5 0
3 years ago
Please someone help I am so lost.
HACTEHA [7]
You'll have to do the actual multiplication here:

  3(n+2)(4n+1)         1        4n^2 + n + 8n + 2
 -------------------- = -----  *  ---------------------------
            6                   2                    1

or (1/2) (4n^2 + 9n + 2), which, after mult., becomes

(1/2)(4n^2) + (1/2)(9n) + 1


This simplifies to 2n^2 + (9/2)n + 1

Therefore, write (1/2) in the first box and (1) in the second box.
7 0
3 years ago
H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?
zubka84 [21]
H(x)=(x^2)+1\ \ \ \ and\ \ \ \  K(x)=-(x^2)+4. \\\\K(H)=-(H^2)+4=-(x^2+1)^2+4=4-(x^2+1)^2=\\\\.\ \ \ =2^2-(x^2+1)^2=(2-x^2-1)(2+x^2+1)=(1-x^2)(3+x^2)=\\\\.\ \ \ =(1-x)(1+x)(x^2-3\cdot i^2)=(1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)\\\\ K(H)=0\ \ \ \ \Leftrightarrow\ \ \ (1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)=0\\\\x=1\ \ \ \ or\ \ \ \ x=-1\ \ \ \ or\ \ \ \ x=\sqrt{3} \cdot i\ \ \ \ or\ \ \ \ x=-\sqrt{3} \cdot i\\\\Ans.\ e.
4 0
2 years ago
A pair of shoes is on sale for $66.00. This is 75% of the original price. What was the original price?
sergejj [24]

Answer:

$88.00

Step-by-step explanation:

66=3/4x

66/.75=66*4/3=88

3 0
2 years ago
Can someone please help me with these 3 math questions? <br> ASAP!
Daniel [21]
I only see one question.
The answer is the root 4 has the multiplicity of 2.
7 0
3 years ago
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