Answer:add me on the gram at n.preme_
Step-by-step explanation:
<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
Answer:
Value of the answer (3¹²)
Step-by-step explanation:
Given:
(3⁵)² / 3⁻²
Find:
Value of the question.
Computation:
⇒ (3⁵)² / 3⁻²
⇒ (3¹⁰) / 3⁻²
⇒ (3¹⁰) (3)²
⇒ (3¹⁰⁺²)
⇒ (3¹²)
⇒ 531,441
Value of the answer = (3¹²)
1. false because the GCF of 101 and 102 is 1 whereas the GCF of 33 and 99 is 33.
2. idk
3. false because the GCF of 1 and 2 is 1
This can be written as (x+4)(x+4)
Multiply everything in the second parenthesis by the x.
x^2 + 4x
Multiply everything in the second parenthesis by 4.
4x + 16
Add these two equations together.
x^2 + 4x + 4x + 16
Combine like terms.
x^2 + 8x + 16
Hope this helps!
