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Irina-Kira [14]

3 years ago

13

Can the triangles be proven similar using the sss or sas similarity theorems? yes, △efg ~ △klm only by sss. yes, △efg ~ △klm onl

y by sas. yes, △efg ~ △klm by sss or sas. no, they cannot be proven similar by sss or sas.

2 answers:

Monica [59]3 years ago

6 0

C i just took the assignment

sattari [20]3 years ago

3 0

The correct answer is c

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Given circle and circle with radii of 6cm and 4cm respectively.

noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

$\angle EAF = \theta = 140^\circ$

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

$=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

= 14.653 cm

In circle C

$\angle GCH = \theta = 140^\circ$

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

$=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

= 9.769 cm

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is 1.5 times the length of GH

i.e. 14.653 = 1.5 x 9.769

14.653 = 14.653

Hence proved.

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3 years ago

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Natali [406]

The correct answer is 15

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3 years ago

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Step-by-step explanation:

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3 years ago