A triangular prism<span> has 5 faces, 3 being rectangular and 2 being </span>triangular<span>. The </span>area<span> of the rectangular faces can be found by multiply the base and height lengths together. The </span>area<span> of the </span>triangular<span> faces can be found by multiplying the base and height and dividing by 2.</span>
Answer:

Step-by-step explanation:
Given the integral equation

According to integration by part;

u = x, dv = e^7x
du/dx = 1
du = dx

Substitute the given values into the formula;

Top left, none
middle, many
top right, one
bottom left, none
if you extend the top and bottom left graphs, they won’t intercept. but if u extend the middle graph, they always intercept. and the top right graph only intercepts once
Answer:
3x(2x^2 +x-1)
Step-by-step explanation:
f(x) = 11x^3 + 3x^2 - 4x + 2,
g(x) = 5x^3 - 7x + 2,
f(x) - g(x) =11x^3+3x^2-4x+2 - (5x^3-7x + 2)=
11x^3+3x^2 -4x+2-5x^3+7x-2=
(11x^3-5x^3)+3x^2+(-4x+7x)+(2-2)=
6x^3 +3x^2 - 3x=
3x(2x^2 +x-1)
Answer:
68
Step-by-step explanation:
We let the random variable X denote the height of students of the college. Therefore, X is normally distributed with a mean of 175 cm and a standard deviation of 5 centimeters.
We are required to determine the percent of students who are between 170 centimeters and 180 centimeters in height.
This can be expressed as;
P(170<X<180)
This can be evaluated in Stat-Crunch using the following steps;
In stat crunch, click Stat then Calculators and select Normal
In the pop-up window that appears click Between
Input the value of the mean as 175 and that of the standard deviation as 5
Then input the values 170 and 180
click compute
Stat-Crunch returns a probability of approximately 68%