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3 years ago

9

Solve for X in the following triangles.X=can someone help me?

2 answers:

Tju [1.3M]3 years ago

8 0

Answer:

x = 67

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the 2 given angles from 180 to obtain x, that is

x = 180° - (62 + 51)° = 180° - 113° = 67°

nevsk [136]3 years ago

6 0

$x=180-(51+62)=180-113=\boxed{67}$

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lina2011 [118]

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3 years ago

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A + (b + c) = (A + b) + c<br><br><br> What property is this equation

Free_Kalibri [48]

Answer:

Step-by-step explanation:

Associative property

7 0

3 years ago

Can someone please answer this

kaheart [24]

Answer:

<h2> ${7}^{3} (as \: a \: single \: power \: of \: 7)$ </h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u> </u></em><em><u> </u></em>

${7}^{4} \div 7$

<em><u>Since</u></em><em><u>,</u></em>

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<em><u>Hence</u></em><em><u>,</u></em>

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8 0

3 years ago

Find the exact value of cos 120° in simplest form with a rational<br> denominator.

IRINA_888 [86]

Given:

cos 120°

To find:

The exact value of cos 120° in simplest form with a rational denominator.

Solution:

We have,

$\cos 120^\circ$

It can be written as

$\cos 120^\circ=\cos (90^\circ+30^\circ)$

$\cos 120^\circ=-\sin 30^\circ$ $[\because \cos (90^\circ-\theta)=-\sin \theta]$

$\cos 120^\circ=-\left(\dfrac{1}{2}\right)$ $[\because \sin 30^\circ=\dfrac{1}{2}]$

$\cos 120^\circ=-\dfrac{1}{2}$

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7 0

3 years ago

Find the inverse of the function. Show work. <br> g(x)= - 3/x-2 +2

4vir4ik [10]

Answer:

$\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}$

Step-by-step explanation:

We are given the function:

$\displaystyle g(x)=-\frac{3}{x-2}+2$

Let's find the inverse of g.

Call y=g(x):

$\displaystyle y=-\frac{3}{x-2}+2$

We need to solve for x. Multiply both sides by x-2 to eliminate denominators:

$y(x-2)=-3+2(x-2)$

Operate:

$yx-2y=-3+2x-4$

Collect the x's to the left side and the rest to the right side of the equation:

$yx-2x=-3-4+2y$

Factor the left side and operate on the right side:

$x(y-2)=-7+2y$

Solve for x:

$\displaystyle x=\frac{-7+2y}{y-2}$

Interchange variables:

$\displaystyle y=\frac{-7+2x}{x-2}$

Call y as the inverse function:

$\boxed{\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}}$

5 0

3 years ago