<em>∙•❁ </em>Okay time to solve this Step-By-Step.<em>❁•∙ </em>
16−<span>2n</span>−5+<span>8n</span>=<span>65
<em>∙•❁ </em>So the first part we need to Simplify both sides of this equation, so:
<span><span><span><span>16−<span>2n</span></span>−5</span>+<span>8n</span></span>=65
<em>∙•❁ </em>We are going to simplify this Step-By-Step.
<span><span><span><span>16−<span>2n</span></span>−5</span>+<span>8n</span></span>=65
</span><span><span><span><span><span><span>16+</span>−<span>2n</span></span>+</span>−5</span>+<span>8n</span></span>=65
<em>∙•❁ </em>Combine like terms:
</span><span><span><span><span>
(<span><span>−2n</span>+8n</span>)</span>+<span>(<span>16+−5</span>)</span></span>=65 </span>
<span><span>6n+11</span>=65
</span><span><span><span>6n</span>+11</span>=65
<em>∙•❁ </em>Now subtract 11 from both sides.
<span><span><span><span>6n</span>+11</span>−11</span>=<span>65−11
</span></span><span><span>6n</span>=54
<em>∙•❁ </em>Now divide both sides by 6 and you'll get your answer:
6n/6=54/6
<em>∙•❁ </em>Your final answer is:
n=9
<em>∙•❁I hope this helps!❁•∙ </em> </span></span></span></span></span>
Answer:
46.15%
Step-by-step explanation:
60/130 = .4615
multiply by 100 to get it into percentage form
46.15%
Answer:
The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 5.4 - 0.04 = 5.36 years.
The upper end of the interval is the sample mean added to M. So it is 5.4 + 0.04 = 5.44 years.
The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.
