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DaniilM [7]
2 years ago
6

Terry practices the same amount of time each day for his soccer tryouts. In 4 days, he has practiced for 360 minutes. Let x repr

esent the number of days Terry practices, and let y represent the number of minutes he practices. Write an equation that could be used to represent this relationship.
Mathematics
1 answer:
n200080 [17]2 years ago
7 0

Answer:

90

Step-by-step explanation:

390 ( 40; 6 )

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Can someone plz help me! I’ve been trying to figure it but I just can’t
VMariaS [17]

Answer:

Step-by-step explanation:

I'll walk you through how to get the answers, but I'm not sure what your drop downs there are asking for.  Maybe once you see the answers, you can figure out how to get the drop downs chosen correctly.

For your quadratic function, the h on the far left is how high the ball is after it is kicked and some amount of time has gone by, the -16t-squared part is the pull of gravity in feet per sec per sec, the 55t is the vertical velocity, and the 1 means that the ball was kicked when it was 1 foot off the ground. If we want to find when ("when" is a time measure) the ball was 45 feet off the ground, we sub in 45 for the h on the far left. Remember that that h is how high the ball is off the ground after it is kicked and some time has gone by. When we sub in 45 for that h, we will solve for t by factoring, to see at what times the ball is 45 feet from the ground.

It would be best to set up the equation and then plug it into the quadratic formula. Subbing in 45 for h gives us:

45=-16t^2+55t+1 and we get everything on one side of the equals sign and set the quadratic equal to 0, giving us:

-16t^2+55t-44=0 and then plug it into the quadratic formula with a = -16, b = 55, and c = -44:

t=\frac{-55+/-\sqrt{55^2-4(-16)(-44)} }{2(-16)}  and we'll simplify that a little at a time:

t=\frac{-55+/-\sqrt{3025-2816} }{-32}  and

t=\frac{-55+/-\sqrt{209} }{-32} giving us 2 solutions:

t=\frac{-55+14.45683229}{-32}=1.2669 sec and

t=\frac{-55-14.45683229}{-32}=2.1705 sec

Let's interpret these solutions. When the ball is kicked up into the air, it experiences parabolic travel. It goes up to a certain max height until gravity wins and the ball comes back down to the ground. Everything thrown up into the air experiences parabolic (or projectile) motion (because gravity affects everything!). So the ball with reach a max height of some number of feet (you could find that out if you needed to, but we'll let that one go for now since this isn't physics class!) before it comes back down.  On its way up to that max height, it will pass the 45 foot mark, and when it's coming back down, it will pass it again. The time that it passes the 45 foot mark going up is 1.2669 seconds after it is kicked. Then it goes up as high as it's going to and comes back down, passing the 45 foot mark on the way back down, at 2.1705 seconds after it was kicked.

However you need to use that interpretation to pick the correct drop-down answer is up to you. Much luck with your quadratics!! They're very important; you haven't seen the last of them by far!

5 0
2 years ago
Plsss help me with this its past due and i need help with it
Blababa [14]

Answer:

y

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Round 1756.18595945 to the nearest thousand.
Readme [11.4K]

Answer:

2,000

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Someone please please help me??
Elena L [17]
Use photomath it works better with functions rather than brainly
7 0
2 years ago
Find the area of the circle with the following dimension.
romanna [79]

Answer:

area=153.9 cm²

Step-by-step explanation:

radius r=Diameter/2=14/2=7 cm

area= π r²=3.14×7²≈153.86 cm²≈153.9 cm²

4 0
2 years ago
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