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DaniilM [7]
2 years ago
6

Terry practices the same amount of time each day for his soccer tryouts. In 4 days, he has practiced for 360 minutes. Let x repr

esent the number of days Terry practices, and let y represent the number of minutes he practices. Write an equation that could be used to represent this relationship.
Mathematics
1 answer:
n200080 [17]2 years ago
7 0

Answer:

90

Step-by-step explanation:

390 ( 40; 6 )

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Answer:

t ≤ -135

Step-by-step explanation:

multiply each side by 5 which then cancels out the 5 in the fraction then turns -27 into -135. Since we multiplied negatives we flipped the sign.

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Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that p = 0.95

10 targets

This means that n = 10

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

P(X = 10) + P(X < 10) = 1

We want P(X < 10). So

P(X < 10) = 1 - P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401

40.1% probability that he will miss at least one of them

7 0
3 years ago
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