Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.
![\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Bhyperbolas%2C%20horizontal%20traverse%20axis%20%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20b%5E2%7D%3D1%20%5Cqquad%20%5Cbegin%7Bcases%7D%20center%5C%20%28%20h%2C%20k%29%5C%5C%20vertices%5C%20%28%20h%5Cpm%20a%2C%20k%29%5C%5C%20c%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%20%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Step-by-step explanation:
120ft³ = 3ft × 4ft × 10ft
120ft³ = 1ft × 1ft × 120ft
120ft³ = 2ft × 2ft × 30ft
120ft³ = 5ft × 3ft × 8ft
...
Taking fractions or mixed numbers as dimensions, you can give infinitely many such shapes with a volume of 120ft³.
Answer:
770000
Step by step explanation:
So we are trying to get the “y” alone, so to undo the division by -8, we will multiply both sides by -8, then simplify.
(-8) y/(-8) = (-8) 1/16
y = -8/16
and simplified:
y = -1/2
Since there is nothing on the left side of the equation besides the absolute value, you have to take 6m out of the absolute value and create 2 separate equations. These 2 equation will be 6m = 42 and 6m = -42.
You solve the equations normally:
6m = 42 6m = -42 (inverse to get m by itself, do on both sides)
/6 /6 /6 /6
m = 7 m = -7
The answer is a solution set:
[7, -7]
