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dlinn [17]
3 years ago
5

Brainliest for a math answer

Mathematics
2 answers:
masya89 [10]3 years ago
7 0
First question is b - a = ___


We know b is 7 and a is 2 so plug it in

7 - 2= 5
5=5
The answer is 5






The second question is b / a = ___


We know b is 18 and a is 2 so plug it in


18/2=9
9=9
The answer is 9
erastovalidia [21]3 years ago
5 0
Question 5- is 9
question 6- is 9
question 7-is 4
question 8-is 21
Question 9-is 2 
question 10-not sure sorry :(



Tell me if your right ;) 


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Forty is 40% less than what number
kirza4 [7]

40 = n-.40n

40 =n(1-.4)

40 = n(.6

divide by .6 on each side

40/.6 =n

n=66 2/3



5 0
3 years ago
Antonio eats 1 slice of pizza in 3 minutes. How long will it take Antonio to eat 4 slices?​
GarryVolchara [31]

Answer:

12 minutes

4*3

That's the answer

8 0
4 years ago
Please help answer this question also with explanation
rodikova [14]
You would have to calculate the percent first.
Add the total number of students
3420+4680= 8100 students TOTAL

Then you would divide the amount of students by the total

3420 part time/8100 students total = .42 or 42%

4680 full time/8100 total = .58 or 58%

Then you multiply the percentages by 90

(90)(.58)= 52.2

(90)(.42)= 37.8

Rounded

52 full time and 38 part time students
5 0
3 years ago
1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0
3 years ago
The price of the book is $4. which expression can be used to show how much money the library will make if it sells 289 books
kogti [31]
If 1 book costs $4 then 289 books will make 289 times as much
so...
(price of book) x (number of books sold) = (amount of money made)
in this case...
4 x 289 = 1156
4 0
3 years ago
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